Multiple choice

In each of the following question, two equations (I) and (II) are given. You have to solve them and answer the question.\newline I. (4x^2 - 12x + 5 = 0)\newline II. (8y^2 + 3y = 38)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solve 4x² - 12x + 5 = 0 by factoring: (2x-1)(2x-5) = 0, giving x = 0.5 or x = 2.5. For 8y² + 3y - 38 = 0, using quadratic formula gives y ≈ -2.44 or y ≈ 1.94. Comparing ranges: x values (0.5, 2.5) vs y values (-2.44, 1.94). Since 2.5 > 1.94 but 0.5 < 1.94, no consistent relationship exists.