The roots $r_1, r_2, r_3, r_4$ of the equations $4x^4-ax^3+bx^2-cx+5=0$ are $+$ve and satisfying $\dfrac{r_1}{2}+\dfrac{r_2}{4}+\dfrac{r_3}{5}+\dfrac{r_4}{8}=1$. The value of c is?
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The roots $r_1, r_2, r_3, r_4$ of the equations $4x^4-ax^3+bx^2-cx+5=0$ are $+$ve and satisfying $\dfrac{r_1}{2}+\dfrac{r_2}{4}+\dfrac{r_3}{5}+\dfrac{r_4}{8}=1$. The value of c is?