Given: 1. class Crivitch { 2. public static void main(String [] args) { 3. int x = 0; 4. // insert code here 5. do { } while (x++ < y); 6. System.out.println(x); 7. } 8. } Which, inserted at line 4, produces the output 12?

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  1. int y = x;

  2. int y = 10;

  3. int y = 11;

  4. int y = 12;

  5. int y = 13;

  6. None of the above will allow compilation to succeed

Show answer
Correct Option: C

AI Explanation

To determine the code that, when inserted at line 4, produces the output 12, let's analyze the given code:

  1. The code starts with a class declaration Crivitch and the main method.
  2. At line 3, the variable x is initialized to 0.
  3. At line 5, there is a do-while loop that continues until x++ is no longer less than y.
  4. At line 6, the value of x is printed.
  5. The code ends with the closing curly braces for the main method and the Crivitch class.

To produce the output 12, we need to find the value of y that satisfies the condition x++ &lt; y until x becomes 12.

Let's go through each option:

Option A) int y = x; This option assigns the value of x to y. Since x is initially 0, y will also be 0. The loop condition x++ &lt; y will never be true, so the loop will not execute. Therefore, this option is incorrect.

Option B) int y = 10; This option assigns the value of 10 to y. Since the loop condition x++ &lt; y starts with x as 0, the loop will execute 11 times (from x = 0 to x = 10). After the loop, x will be incremented to 11 and printed. Therefore, this option is incorrect.

Option C) int y = 11; This option assigns the value of 11 to y. Since the loop condition x++ &lt; y starts with x as 0, the loop will execute 12 times (from x = 0 to x = 11). After the loop, x will be incremented to 12 and printed. Therefore, this option is correct.

Option D) int y = 12; This option assigns the value of 12 to y. Since the loop condition x++ &lt; y starts with x as 0, the loop will execute 13 times (from x = 0 to x = 12). After the loop, x will be incremented to 13 and printed. Therefore, this option is incorrect.

Option E) int y = 13; This option assigns the value of 13 to y. Since the loop condition x++ &lt; y starts with x as 0, the loop will execute 14 times (from x = 0 to x = 13). After the loop, x will be incremented to 14 and printed. Therefore, this option is incorrect.

Option F) None of the above will allow compilation to succeed. This option is incorrect because options B, C, D, and E would all allow compilation to succeed.

Therefore, the correct answer is option C) int y = 11. This option will produce the output 12.

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