public static void main(String[] args) {
  String str = "null"; 
 if (str == null) {
  System.out.println("null");
  } else (str.length() == 0) {
  System.out.println("zero");
  } else {
  System.out.println("some");
  }  
}    

What is the result?

  1. null

  2. zero

  3. some

  4. Compilation fails


Correct Option: D
Explanation:

To solve this question, the user needs to know that the given code is testing whether a string value is null or empty. They also need to know the syntax of if-else statements in Java.

Now, let's go through each option and explain why it is right or wrong:

A. null: This option is incorrect because the code checks if the string is null using the expression str == null, which evaluates to false since str is "null" (a non-null string literal).

B. zero: This option is incorrect because the code does not check if the string is empty using the expression str.length() == 0. Instead, it tries to use an invalid syntax by placing an else block after the if block. This leads to a compilation error.

C. some: This option is incorrect because the code won't reach this block due to the compilation error mentioned above.

D. Compilation fails: This option is correct. The code will fail to compile due to the invalid syntax in the else block. The correct syntax for an if-else statement is:

if (condition) {
    // code block for true case
} else {
    // code block for false case
}

Therefore, the correct code should be:

public static void main(String[] args) {
  String str = "null"; 
  if (str == null) {
    System.out.println("null");
  } else if (str.length() == 0) {
    System.out.println("zero");
  } else {
    System.out.println("some");
  }  
}

The Answer is: D

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