what is the output? main() { int x=20,y=35; x=y++ + x++; y= ++y + ++x; printf(“%d \t %dn”,x,y); }

To determine the output of the given code, let's go through each line of code step by step:

1. int x=20, y=35;

   • This line initializes two integer variables, x with a value of 20 and y with a value of 35.

2. x=y++ + x++;

   • In this line, the expression y++ + x++ is evaluated.
   • The postfix increment operator ++ increments the value of y after it has been used in the expression.
   • The value of y++ is 35, and the value of x++ is 20.
   • So, x = 35 + 20, resulting in x = 55.
   • After the evaluation, the value of x is incremented by 1 due to the postfix increment, making it 21.
   • The value of y is incremented by 1 due to the postfix increment as well, making it 36.

3. y= ++y + ++x;

   • In this line, the expression ++y + ++x is evaluated.
   • The prefix increment operator ++ increments the value of y and x before they are used in the expression.
   • The value of ++y is 37, and the value of ++x is 22.
   • So, y = 37 + 22, resulting in y = 59.
   • After the evaluation, the value of x is incremented by 1 due to the prefix increment, making it 23.
   • The value of y is incremented by 1 due to the prefix increment as well, making it 60.

4. printf("%d \t %dn", x, y);

   • This line prints the values of x and y using the printf function.
   • The format specifier %d is used to print integer values.
   • The format specifier %t is used to print a horizontal tab character.
   • The format specifier %n is not a valid specifier.

So, the correct output will be 57 94. Therefore, the correct answer is B.

• Thanks
• Wrong explanation