To determine the output of the given code, let's go through each line of code step by step:

1. int x=20, y=35;

   • This line initializes two integer variables, x with a value of 20 and y with a value of 35.

2. x=y++ + x++;

   • In this line, the expression y++ + x++ is evaluated.
   • The postfix increment operator ++ increments the value of y after it has been used in the expression.
   • The value of y++ is 35, and the value of x++ is 20.
   • So, x = 35 + 20, resulting in x = 55.
   • After the evaluation, the value of x is incremented by 1 due to the postfix increment, making it 21.
   • The value of y is incremented by 1 due to the postfix increment as well, making it 36.

3. y= ++y + ++x;

   • In this line, the expression ++y + ++x is evaluated.
   • The prefix increment operator ++ increments the value of y and x before they are used in the expression.
   • The value of ++y is 37, and the value of ++x is 22.
   • So, y = 37 + 22, resulting in y = 59.
   • After the evaluation, the value of x is incremented by 1 due to the prefix increment, making it 23.
   • The value of y is incremented by 1 due to the prefix increment as well, making it 60.

4. printf("%d \t %dn", x, y);

   • This line prints the values of x and y using the printf function.
   • The format specifier %d is used to print integer values.
   • The format specifier %t is used to print a horizontal tab character.
   • The format specifier %n is not a valid specifier.

So, the correct output will be 57 94. Therefore, the correct answer is B.

• Thanks
• Wrong explanation

To answer this question, let's go through the code step by step:

main() {
    char *p1 = "name";
    char *p2;
    p2 = (char*)malloc(20);
    memset(p2, 0, 20);
    while (*p2++ = *p1++);
    printf("%sn", p2);
}

First, we declare two character pointers p1 and p2.

p1 is assigned the address of a string literal "name".

p2 is allocated memory using malloc(20) and the memory is initialized to 0 using memset(p2, 0, 20).

Next, there is a while loop: while (*p2++ = *p1++). This loop copies the characters from p1 to p2 until it encounters the null character ('\0') at the end of the string.

After the while loop, p2 is pointing to the null character at the end of the copied string.

Finally, printf("%sn", p2) is used to print the contents of p2.

Since p2 is pointing to the null character at the end of the copied string, it will print an empty string.

Therefore, the correct answer is C) empty string.

• Thanks
• Wrong explanation