What will be the output of “echo this || echo that && echo other”?
-
a. this
-
b. this other
-
c. that
-
d. this that other
In shell, 'echo this || echo that && echo other' works as follows: 'echo this' executes successfully (returns 0), so 'echo that' after || is skipped (|| only runs if previous failed). Since 'echo this' succeeded, 'echo other' after && runs. Output is 'this' followed by 'other' on the next line.
To answer this question, let's break down the given command: "echo this || echo that && echo other"
The "||" operator is the logical OR operator in shell scripting. It executes the command on the right side only if the command on the left side fails (returns a non-zero exit status).
The "&&" operator is the logical AND operator in shell scripting. It executes the command on the right side only if the command on the left side succeeds (returns a zero exit status).
Now let's go through each part of the command step by step:
"echo this" - This command will be executed first. It will output "this".
"echo that" - Since the previous command succeeded, this command will not be executed. So, "that" will not be outputted.
"echo other" - Since the previous command succeeded, this command will be executed. It will output "other".
Therefore, the output of the given command "echo this || echo that && echo other" will be "this other".
The correct answer is Option B: "this other".