What will be the output of the following program : #define Swap if (a != b) { \ temp=a; \ a = b; \ b = temp; \ //Swapping Done } void main() { int a=10,b=5,temp; Swap; printf("a=%d a=%d",a,b); }
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Compile-Time Error
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a=5 b=10
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a=10 b=5
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None of the above
A
Correct answer
Explanation
The macro definition has malformed backslashes - they should only appear at line endings for continuation, not before each statement. Also, the macro call 'Swap;' lacks proper syntax. The preprocessor will fail to parse this correctly, resulting in a compilation error.