To answer this question, we need to understand the concept of type conversion in programming.

Type conversion refers to the process of converting a value from one data type to another. In most programming languages, certain conversions are allowed, while others may not be possible or may result in loss of information.

Let's go through each option to understand why it is correct or incorrect:

Option A) int to float - This option is possible because it involves converting an integer value to a floating-point value. This conversion is allowed, and the integer value can be represented as a floating-point number.

Option B) float to int - This option is possible because it involves converting a floating-point value to an integer value. This conversion is allowed, but it may result in the loss of the decimal part of the floating-point value.

Option C) char to float - This option is possible because it involves converting a character value to a floating-point value. This conversion is allowed, and the character can be represented as its corresponding ASCII value, which can be stored as a floating-point number.

Option D) All are possible - This option is incorrect because there is one conversion that is not possible. The correct answer is D because not all conversions are possible.

The correct answer is D. This option is incorrect because there is one conversion that is not possible.

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• Wrong explanation

To answer this question, let's go through the given program step by step:

1. The program starts by declaring a variable val and initializing it with the value 5.
2. Then, a void pointer ptr is declared.
3. The next line *(int *)ptr=5; tries to assign the value 5 to the memory location pointed by ptr. However, since ptr is not pointing to any valid memory location, this line will result in undefined behavior. This is because ptr is uninitialized and pointing to an unknown memory location.
4. Next, the line val=ptr; tries to assign the value of ptr to val. Since ptr is uninitialized, this will also result in undefined behavior.
5. Finally, the line printf("%d %d",*(int *)val,*(int *)ptr); tries to print the values at the memory locations pointed by val and ptr. However, since both val and ptr are uninitialized and not pointing to valid memory locations, this will also result in undefined behavior.

Therefore, the correct answer is option A) Compile-Time Error.

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• Wrong explanation

To answer this question, let's go through the options one by one:

Option A) 123 - This option is incorrect because the code includes a format specifier "%f" in the printf function. This format specifier is used to print floating-point numbers, and it specifies that the number should be printed with six digits after the decimal point.

Option B) Compile-Time Error - This option is incorrect. The code does not contain any syntax errors, so it will compile successfully.

Option C) 123.00 - This option is incorrect. Although the number 123 is a whole number, the format specifier "%f" specifies that the number should be printed with six digits after the decimal point. Since there are no digits after the decimal point in the number 123., it will be printed as 123.000000.

Option D) 123.000000 - This option is correct. The code includes a format specifier "%f" in the printf function, which specifies that the number should be printed with six digits after the decimal point. Since there are no digits after the decimal point in the number 123., it will be printed as 123.000000.

The correct answer is D) 123.000000.

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• Wrong explanation