public class AQuestion{ public static void main(String args[]){ System.out.println("Before Try"); try{ } catch(Throwable t){ System.out.println("Inside Catch"); } System.out.println("At the End"); } }

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  1. Compiler error complaining about the catch block where no IOException object can ever be thrown.

  2. Compiler error - IOException not found. It must be imported in the first line of the code.

  3. No compiler error. The lines “Before Try” and “At the end” are printed on the screen.

  4. None of Above

Show answer
Correct Option: A,B,C,D

AI Explanation

To answer this question, let's go through each option:

Option A) Compiler error complaining about the catch block where no IOException object can ever be thrown. This option is incorrect. The catch block doesn't specify any specific exception type, so it can catch any type of exception or throwable object.

Option B) Compiler error - IOException not found. It must be imported in the first line of the code. This option is incorrect. The code doesn't throw any IOException, so there is no need to import it.

Option C) No compiler error. The lines “Before Try” and “At the end” are printed on the screen. This option is correct. Since there are no statements inside the try block, the code will execute the statements after the try-catch block. Therefore, the output will be "Before Try" followed by "At the End".

Option D) None of the Above This option is incorrect since option C is correct.

The correct answer is C. No compiler error. The lines “Before Try” and “At the end” are printed on the screen because there are no statements inside the try block.

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