To answer this question, let's go through each option:

Option A) Compiler error complaining about the catch block where no IOException object can ever be thrown. This option is incorrect. The catch block doesn't specify any specific exception type, so it can catch any type of exception or throwable object.

Option B) Compiler error - IOException not found. It must be imported in the first line of the code. This option is incorrect. The code doesn't throw any IOException, so there is no need to import it.

Option C) No compiler error. The lines “Before Try” and “At the end” are printed on the screen. This option is correct. Since there are no statements inside the try block, the code will execute the statements after the try-catch block. Therefore, the output will be "Before Try" followed by "At the End".

Option D) None of the Above This option is incorrect since option C is correct.

The correct answer is C. No compiler error. The lines “Before Try” and “At the end” are printed on the screen because there are no statements inside the try block.

• Thanks
• Wrong explanation

To answer this question, we need to understand the concept of inheritance and typecasting.

The given code defines two classes: MyCast and Base. The class Base extends the class MyCast, indicating that Base inherits from MyCast.

In the main method, two objects are instantiated: m of type MyCast and b of type Base. Now, let's go through each option to determine which one allows the code to compile and run without error when inserted at the comment //………..Here.

Option A) b = m; This option attempts to assign m to b. However, m is of type MyCast, and b is of type Base. Since Base inherits from MyCast, we can assign a Base object to a MyCast reference, but not the other way around. Therefore, this option is incorrect.

Option B) m = b; This option attempts to assign b to m. Since Base extends MyCast, a Base object can be treated as a MyCast object. Therefore, this option is correct.

Option C) d = i; This option attempts to assign the value of i to d. However, i is of type int, and d is of type double. The assignment may result in a loss of precision, which is not allowed without explicit casting. Therefore, this option is incorrect.

Option D) b1 = i; This option attempts to assign the value of i to b1. However, i is of type int, and b1 is of type boolean. The types are not compatible, and this assignment is not allowed. Therefore, this option is incorrect.

The correct answer is Option B) m = b;. This option allows the code to compile and run without error because a Base object can be assigned to a MyCast reference.

• Thanks
• Wrong explanation