Multiple choice java

What is the output of the following code when compiled and run? Select two correct answers. 

public class Question59 {   
     public static void main(String[] args) { 
        String String = "String"; //line 1
        int Question59 = 2;         //line 2
        for(int main=0;mainQuestion59)      //line 5
                break Object;       //line 6
        }
    }
  }

  1. Prints: t i g

  2. Prints: S r n

  3. Compilation error at lines 1, 2 and 3.

  4. Compilation error at lines 4, 5 and 6.

  5. The code compiles and runs fine.
Reveal answer Fill a bubble to check yourself
B,E Correct answer
Explanation

The code uses reserved words as variable names (String, Question59, main) which is legal in Java. The loop iterates: main=0 prints 'S', main=2 prints 'r', main=4 prints 'n', main=6 exceeds 2 and breaks. Output: 'S r n'. The break statement syntax is incorrect (should be 'break;' not 'break Object;'), but since the break executes before the labeled syntax error is reached, the code runs. Option E states the code compiles and runs, which is true despite the unreachable labeled break.

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