Tag: chemistry

Questions Related to chemistry

When excess of ammonia is used:


 $3Cl _2+8NH _3$$\longrightarrow$$A+B$

When excess of chlorine is used:

$3Cl _2+4NH _3$$\longrightarrow$$C+D$

The oxidation state of nitrogen in compound $A$ is:

  1. $-3$

  2. $+3$

  3. $+5$

  4. $0$


Correct Option: A
Explanation:

$8 NH _3 + 3 Cl _2 \rightarrow  6 NH _4Cl+N _2$

 Compound A is $NH _4Cl$ 

$1(x)+4(1)+1(-1)=0$

$x+4-1=0$

$x=-3$

The oxidation state of compound A is $-3$

Hence option A is correct.

When excess of ammonia is used:
 $3Cl _2+8NH _3$$\longrightarrow$$A+B$
When access of chlorine is used:
$3Cl _2+4NH _3$$\longrightarrow$$C+D$
Oxidation state of nitrogen in compound $B$ is:

  1. $0$

  2. $+1$

  3. $+3$

  4. $-3$


Correct Option: A
Explanation:

$8 NH _3 + 3 Cl _2 \rightarrow  6 NH _4Cl+N _2$

$3Cl _2+4NH _3 \rightarrow  3NH _4Cl+NCl _3$

 Compound  B is $N _2$ Here as the nitrogen is in elemental state so its oxidation state is $0$

 Hence option A is correct.

Which of the following compounds will not undergo azo coupling reaction with benzene diazonium chloride?

  1. Aniline

  2. Phenol

  3. Anisole

  4. Nitrobenzene


Correct Option: D
Explanation:

Diazonium cation is weak electrophile and hence it reacts with electron rich compounds containing electron donating groups such as $-OH$, $-NH _2$ and $OCH _3$ groups and not with compounds containing electron withdrawing groups such as $-NO _2$ etc.


Hence,option D is correct.

Which of the following diazonium salt is relatively stable of $0-5^o$C?

  1. $CH _3CH _2N\equiv N}^{\oplus}Cl^-$

  2. $CH _3-C(CH _3) _2-N\equiv N}^{\oplus} Cl^-$

  3. $CH _3-N\equiv N}^{\oplus}Cl^-$

  4. $(CH _3) _3C-N\equiv N}^{\oplus}Cl^-$


Correct Option: C

Which of the following diazonium salt is relatively stable at $0-{ 5^0 }^{ }C$?

  1. ${ CH } _{ 3 }-N\equiv N{ } }^{ \oplus }C{ l }^{ - }$

  2. ${ \left( { CH } _{ 3 } \right) } _{ 2 }CH-N\equiv N{ } }^{ \oplus }{ Cl }^{ - }$

  3. ${ C } _{ 6 }{ H } _{ 5 }-N\equiv N{ } }^{ \oplus }{ Cl }^{ - }$

  4. ${ \left( { CH } _{ 3 } \right) } _{ 3 }C-N\equiv N{ } }^{ \oplus }{ Cl }^{ - }$


Correct Option: D
Explanation:

The $+I$ effect which stabilizes the ${ N }^{ + }$ion is in the following order ${ C } _{ 6 }{ H } _{ 5 }-<{ CH } _{ 3 }-<{ \left( { CH } _{ 3 } \right)  } _{ 2 }-<{ \left( { CH } _{ 3 } \right)  } _{ 3 }$

$\therefore $ The ${ \left{ { \left( { CH } _{ 3 } \right)  } _{ 3 }C-N\equiv N \right}  }^{ + }{ Cl }^{ - }$ is most stable

Which of the following is an Incorrect statement about benzenediazonium chloride?

  1. It is prepared by the reaction of aniline with nitrous acid at 273-278 K

  2. It is a colourless crystalline solid

  3. Alkyl diazonium salts are more stable than arenediazonium salts

  4. Benzene diazonium fluoroborate is water insoluble & stable at room temperature


Correct Option: C

For the successful diazotisation of arylamines, how many mole of mineral acid $(HCl \quad or \quad H _2SO _4 )$ are required for each mole of the amine?

  1. 1

  2. 2

  3. 3

  4. 4


Correct Option: C

In an analytical determination of arsenic, a solution containing arsenious acid, $ H _{3}AsO _{4},$ KI and a small amount of starch is electrolysed. The electrolysis produces free $I _{2}$ from $ I^{-}$ ions and the $ I _{2}$ immediately oxidizes the arsenious acid to hydrogen arsenate ion, $ HAsO _{4}^{2-}.$
$ I _{2}+H _{3}AsO _{3}+H _{2}O \rightarrow 2I^{-} + HAsO _{4}^{2-}+4H^{+}$
When the oxidation of arsenic is complete, the free iodine blue colour. If during a particular run, it takes 96.5 s for a current of 10.0 mA to give an end point (indicated by the blue colour),how many g of arsenic are present in the solution. (As = 75)

  1. $ 6.3 \times 10^{-4} g$

  2. $1.26 \times 10^{-4}g$

  3. $ 3.15 \times 10^{-5}g$

  4. $ 6.3 \times 10^{-5}g$


Correct Option: D

State, whether the following statements are True or False:
Aniline forms phenol when treated with nitrous acid.

  1. True

  2. False


Correct Option: B

Which of the following amines form unstable diazonium salt?

  1. ${ C } _{ 6 }{ H } _{ 5 }{ NH } _{ 2 }$

  2. $\left( { C } _{ 2 }{ H } _{ 5 } \right) _{ 2 }NH$

  3. $\left( { C } _{ 2 }{ H } _{ 5 } \right) _{ 3 }N$

  4. ${ CH } _{ 3 }{ NHC } _{ 2 }{ H } _{ 5 }$


Correct Option: B,C,D
Explanation:

Only primary aromatic amines form stable arene diazonium salts.
The reaction is as follows:

$C _{6}H _{5}NH _{2} + NaNO _{2} + HCl (0-5^{\circ}C) \rightarrow PhN _{2}^{+}Cl^{-}$

Remain forms the unstable diazonium salt.
So, the correct options are $B$, $C$, $D$