Tag: chemistry

Questions Related to chemistry

Give a balanced reaction in which ammonia is oxidised by a metal oxide.

  1. ${ 4NH } _{ 3 }+3CuO\rightarrow 2{ N } _{ 2 }+{ 3H } _{ 2 }O+3Cu$

  2. ${ 2NH } _{ 3 }+4CuO\rightarrow { N } _{ 2 }+{ 3H } _{ 2 }O+4Cu$

  3. ${ 2NH } _{ 3 }+CuO\rightarrow { N } _{ 2 }+{ 3H } _{ 2 }O+Cu$

  4. ${ 2NH } _{ 3 }+3CuO\rightarrow { N } _{ 2 }+{ 3H } _{ 2 }O+3Cu$


Correct Option: D
Explanation:

${ 2NH } _{ 3 }+3CuO\rightarrow { N } _{ 2 }+{ 3H } _{ 2 }O+3Cu$

Which of the following does not react with $AgCl$?

  1. $Na _{2}S _{2}O _{3}$

  2. $NH _{4}OH$

  3. $NaNO _{3}$

  4. $NH _{3}$


Correct Option: C
Explanation:

$AgCl+2NH _{4}OH\rightarrow \left [ Ag(NH _{3}) _{2} \right ]Cl+2H _{2}O$
$AgCl+2Na _{2}S _{2}O _{3}\rightarrow NaCl+Na _{3}\left [ Ag(S _{2}O _{3}) _{2} \right ]$
$AgCl+NH _{3}\rightarrow \left [ Ag(NH _{3}) _{2} \right ]Cl$
So, only $NaNO _{3}$ does not react with AgCl.

Ammonia on reaction with hypochlorite anion forms :

  1. $\mathrm{N}\mathrm{O}$

  2. $\mathrm{N}\mathrm{H} _4Cl$

  3. $\mathrm{N} _{2}\mathrm{H} _{4}$

  4. $\mathrm{H}\mathrm{N}\mathrm{O} _{2}$


Correct Option: C
Explanation:

$2NH _{3} + OCl^{-} \rightarrow N _{2}H _{4} + Cl^{-} + H _{2}O$

The bottles of liquid ammonia are opened after cooling them in ice for sometime. It is because liquid ammonia :

  1. has high vapour pressure at room temperature

  2. is corrosive liquid

  3. is an explosive

  4. brings tears in eyes


Correct Option: A
Explanation:

Liquid ammonia has hydrogen bonding which results in high vapour pressure at room temperature.


The vapour pressure of ammonia at room temperature is very high and hence the ammonia will evaporate unless the vapour pressure is decreased. 

Cooling decreases the vapour pressure so that the liquid remains in the same state. Hence, the bottle is cooled before opening.

Option A is correct.

Which of the following would lose weight when exposed to the atmosphere?

  1. Concentrated ${H} _{2}{SO} _{4}$

  2. Anhydrous ${Na} _{2}{CO} _{3}$

  3. Solid $NaOH$

  4. A saturated solution of ammonia in water


Correct Option: D
Explanation:

${ NH } _{ 3 }$ is highly soluble in water.

Solution of ammonia in water is called liquor ammonia.
Liquor ammonia is highly volatile in nature and has a high latent heat of evaporation.
Hence, it will lose weight when exposed to atmosphere.

Liquid ammonia is a fuel for:

  1. motorcar

  2. aeroplane

  3. monorial

  4. rocket


Correct Option: D
Explanation:

Hydrogen is good fuel. $1$ mole of ammonia has more hydrogen than hydrogen fuel. It burns to give water and nitrogen. 

$NH _3$ is used as a fuel in rockets due to its high energy density.

It is a carbon-free fuel which is combined with liquid oxygen in rockets fuel tanks.

Another advantage is that due to its strong, pungent odour, they can be easily identified in case of fuel leakage.

Hence, option D is correct.

The ion or group detected by $K _2[HgI _4]$ is:

  1. NO

  2. $Cl^-$

  3. $NH^{-2}$

  4. $NH _3$


Correct Option: D
Explanation:

${ K } _{ 2 }[Hg{ I } _{ 4 }]$ ( potassium mercuric iodide) is known as nesseler's reagent.

It is used for the detection of ammonia.
The reaction taking place is:
$2{ K } _{ 2 }[Hg{ I } _{ 4 }]+3KOH+{ NH } _{ 3 }\rightarrow [{ OHg } _{ 2 }.{ NH } _{ 2 }]I+7KI+2{ H } _{ 2 }O$
The colour of nesseler's reagent changes to brown in basic medium.

When $Na$ reacts with liquid $NH _3$ the following substance is formed: 

  1. $[Na(NH _3) _x]^- $

  2. $ [e(NH _3 ) _y]^-$

  3. $NaNH _2$

  4. $Na _xNH _{3y}$


Correct Option: B
Explanation:

Sodium (Na) dissolves in liquid ammonia ($NH _3$) solution to form a blue colored solution characteristic of a solvated electron in liquid ammonia which is conducting in nature due to presence of solvated electrons.

Reaction is  $ Na + (x+y)NH _3\rightarrow Na(NH _3) _x + (e(NH _3) _y)^-$
So B is correct answer. 

Ammonia and the ammonium ion can be differenciated by:

  1. an neutron

  2. a proton

  3. a electron

  4. hydroxide


Correct Option: B
Explanation:

Ammonia and the ammonium ion can be differentiated by a proton $\displaystyle (H^+)$.
Ammonia is $\displaystyle NH _3$ and ammonium ion is $\displaystyle NH _4^+$.
$\displaystyle NH _3 + H^+ \rightarrow NH _4^+$

$\displaystyle Al{ Cl } _{ 3 }\left( aq \right) +{ NH } _{ 3 }\left( aq \right) + { H } _{ 2 }O\rightarrow $
Which of the following is one of the products obtained from the reaction above?

  1. $\displaystyle AlN$

  2. $\displaystyle Al{ H } _{ 3 }$

  3. $\displaystyle Al$

  4. $\displaystyle { Al\left( { NO } _{ 3 } \right) } _{ 3 }$

  5. $\displaystyle { Al\left( OH \right) } _{ 3 }$


Correct Option: E
Explanation:

${ AlCl } _{ 3 }+3{ NH } _{ 3 }+3{ H } _{ 2 }O\rightarrow Al\left( OH \right) _{ 3 }+3{ NH } _{ 4 }Cl$