Tag: chemistry

Questions Related to chemistry

Who determined the mass of a neutron?

  1. John Dalton (early 1800's)

  2. Ernest Rutherford (1911)

  3. Niels Bohr (1913)

  4. James Chadwick (1932)


Correct Option: D
Explanation:

The presence of neutron and its mass was determined by James Chadwick. Neutron was discovered by bombarding $\alpha-$particles on $Be$. On doing so, highly energetic beam of radiation was observed by Chadwick. Thus mass of neutron was determined by James Chadwick.

Whose experiment proved the existence of the nucleus?

  1. John Dalton (early 1800's)

  2. Ernest Rutherford (1911)

  3. Niels Bohr (1913)

  4. James Chadwick (1932)


Correct Option: B
Explanation:

The $\alpha-$ ray scattering-gold foil experiment by Ernest Rutherford gave substantial evidence for  existence of nucleus in $1911$. Thus the existence of nucleus was proved by Rutherford's experiment.

Neutron was discovered by:

  1. J.J. Thomson

  2. Chadwick

  3. Rutherford

  4. Priestley


Correct Option: B
Explanation:

 Neutron was discovered by Chadwick.
To overcome the failure of proton electron hypothesis, Rutherford, in 1920, proposed the existence of neutral particle made from close combination of proton and electron. He named it neutron.
In 1932, Lord Chadwick proved the existence of neutron by bombarding lighter elements (boron and beryllium) with alpha particles which resulted in the emission of highly penetrating neutral radiation.

The neutron is a neutral (non-electrical) particle in the centre of the atom. It was discovered when a tiny piece of the metal, beryllium, was bombarded with alpha particles. This discovery was made by:

  1. Chadwick

  2. Rutherford

  3. Niels Bohr

  4. Enrico Fermi


Correct Option: A
Explanation:
In 1930, it was discovered that Beryllium, when bombarded by alpha particles, emitted a very energetic stream of neutral radiation. In 1932, Chadwick proposed that neutral radiation consists of a new type of neutral particles - neutrons.

A translucent white waxy solid (A) reacts with excess of chlorine to give a yellowish white powder (B). (B) reacts with organic compounds containing -OH group converting them into chloro derivatives. (B) on hydrolysis gives (C) and is finally converted to phosphoric acid. (A), (B) and (C) are?

  1. $P _{4}$,$PCl _{3}$,$H _{3}PO _{4}$

  2. $P _{4}$,$PCl _{5}$,$H _{3}PO _{3}$

  3. $P _{4}$,$PCl _{5}$,$POCl _{3}$

  4. $P _{4}$,$PCl _{3}$,$POCl _{3}$


Correct Option: C
Explanation:

A translucent white waxy solid (A) reacts with excess of chlorine to give a yellowish white powder (B). Here B is $PCl _5$.$PCl _5$ reacts with organic compounds containing -OH group converting them into chloro derivative $POCl _3. $.$PCl _5$ on hydrolysis gives (C).C is $POCl _3$ and is finally $POCl _3$ converted to phosphoric acid.

So  (A), (B) and (C) are $P _{4}$,$PCl _{5}$,$POCl _{3}$.

Hence option C is correct.

$\mathrm{P}\mathrm{Cl} _{3}$ is prepared by the action of $\mathrm{Cl} _{2}$ on :

  1. $ \mathrm{P} _{2}\mathrm{O} _{3}$

  2. $ \mathrm{P} _{2}\mathrm{O} _{5}$

  3. White $\mathrm{P}$

  4. $\mathrm{H} _{3}\mathrm{P}\mathrm{O} _{3}$


Correct Option: C
Explanation:

White P is reactive due to strain.
$P _{4}+6Cl _{2}\ \to \ 4PCl _{3}$
(White P)

Which of the following exist as dimer :

  1. NO

  2. $NO _{2}$

  3. $P _{2}O _{3}$

  4. All


Correct Option: D
Explanation:

All have dimer forms

$NO$ as $N _{2}O _{2}$

$NO _{2}$ as $N _{2}O _{4}$

$P _{2}O _{3}$ as $P _{4}O _{6}$

What is the oxidation state of Phosphorus in ${P}{Cl} _{3}$?

  1. ${+}{5}$

  2. ${+}{3}$

  3. ${+}{1}$

  4. ${-}{3}$


Correct Option: B
Explanation:

The oxidation state of ${P}$ in ${P}{Cl} _{3}$ is ${+3}$.
Each Chlorine atom has an oxidation number of ${-1}$. There are three chlorine atoms, hence the total oxidation number of the Chloride ions in ${-3}$. ${PCl} _{3}$ molecule is neutral. Hence the oxidation number of Phosphorus should be ${+3}$

What is the boiling point of ${PCl} _{3}$?

  1. ${-93.6}^{o}$ ${C}$

  2. ${169}^{o}$ ${C}$

  3. ${100}^{o}$ ${C}$

  4. ${76.1}^{o}$ ${C}$


Correct Option: D
Explanation:

The boiling point of ${PCl} _{3}$ is ${76.1}^{o}$ ${C}$

What is the hybridization of Phosphorus Trichloride?

  1. ${sp}^{3}$

  2. ${sp}^{2}$

  3. ${sp}$

  4. None of these


Correct Option: A
Explanation:

The hybridization of ${PCl} _{3}$ is ${sp}^{3}$. Phosphorus has five electrons in its outermost shell. Thus it forms three sigma bonds with three neighbouring Chlorine atoms. The remaining two electrons remain as a lone pair on Phosphorus atom. Thus these three sigma bonds and one lone pair, make this molecule ${sp}^{3}$ hybridized.