Tag: chemistry

Questions Related to chemistry

Which of the following is least basic?

  1. NF3N

  2. NH3

  3. NCl3

  4. NI3


Correct Option: A

In which case of mixing a strong acid and a base each of $1$N concentration, temperature rise is highest?

  1. $20$ ml, acid + $30$ ml alkali

  2. $10$ ml, acid + $40$ ml alkali

  3. $20$ ml, acid + $20$ ml alkali

  4. $30$ ml, acid + $20$ ml alkali


Correct Option: C
Explanation:

More amount of acid reacts with equal amount of base, higher the amount of heat releases.

So, $20ml$ of acid+$20ml$ of alkali.

Conjugate base of ${ H } _{ 3 }{ PO } _{ 4 }$?

  1. ${ H } _{ 2 }{ PO } _{ 4 }^{ - }$

  2. ${ H } _{ }{ PO } _{ 4 }^{ 2- }$

  3. ${ H } _{ 4 }{ PO } _{ 4 }^{ + }$

  4. ${ H } _{ 3 }{ PO } _{ 4 }^{ }$


Correct Option: A
Explanation:

${H _2PO _4}^-$ is conjugate base of $H _3PO _4$  .

$H _2O _2$ is a:

  1. monobasic acid

  2. dibasic acid

  3. neutral compound

  4. weal alkali


Correct Option: B
Explanation:
A dibasic molecule has two replaceable hydrogen atoms. Since $H _2O _2$ has two replaceable hydrogen atoms, That's why it is a dibasic acid.

$H _2O _2\rightarrow HO _2^−+H^+$

$HO _2^−\rightarrow O _2^{−2}+H^+$


$\mathbf{Hence\ the\ correct\ answer\ is\ option\ (B)}$

Effective charge on each oxygen is $-\frac{1}{4}$ in?

  1. $SO _{3}^{2-}$

  2. $SO _{3-}^{4}$

  3. $ClO _{3}^{-}$

  4. $ClO _{4}^{-}$


Correct Option: C

Among ${ KO } _{ 2 },{ AIO } _{ 2 }^{ - },{ BaO } _{ 2 }\ and\ { NO } _{ 2 }^{ + }$, unpaired electron is present in :

  1. ${ NO } _{ 2 }^{ + }\quad and\quad { BaO } _{ 2 }$

  2. ${ KO } _{ 2 }\quad and\quad AI{ O } _{ 2 }^{ - }$

  3. ${ KO } _{ 2 }$ only

  4. $Ba{ O } _{ 2 }$ only


Correct Option: C
Explanation:

This can be done by counting number of valence electrons


$KO _2=1+2\times 6=17$-Odd number of electrons and hence unpaired.


$AlO^{2-} _2=3+2\times 6+1=14$-Even number of electrons and hence paired.

$BaO _2=2+2\times6=14$-Even number of electrons and hence paired.

$NO^{+} _{2}=5+2\times6 -1=16$-Even number of electrons and hence paired.

Hence option C is the correct answer.

Which has highest specific charge?

  1. $Na^{+}(mass\ no\ =23)$

  2. $Mg^{2+}(mass\ no\ =24)$

  3. $Al^{+3}(mass\ no\ =27)$

  4. $Si^{+4}(mass\ no\ =28)$


Correct Option: D
Explanation:

Specific charge in the ratio of charge of ion to its mass.

Specific charge $=\dfrac { e }{ M } $
For ${ Na }^{ + }=\dfrac { e }{ 23 } ,\quad $ for ${ Mg }^{ 2+ }=\dfrac { 2\times e }{ 24 } $
For ${ Al }^{ 3+ }=\dfrac { 3\times e }{ 27 } ,\quad $ for ${ Si }^{ 4+ }=\dfrac { 4\times e }{ 28 } $
In is in the following order,
${ Si }^{ 4+ }>{ Al }^{ 3+ }>{ Mg }^{ 2+ }>{ Na }^{ + }$

In bisulphate ion, the formal charge on sulphur atom is:

  1. $+1$

  2. $+2$

  3. $+4$

  4. $+6$


Correct Option: B

Formal charge on nitrogen and oxygen in $NO^- _3$ ion are respectively: 

  1. $0, \dfrac{-1}{3}$

  2. $+1, \dfrac{-1}{3}$

  3. $+1, \dfrac{-2}{3}$

  4. $0, \dfrac{-2}{3}$


Correct Option: A
Explanation:

Formula change is basically a change given to an atom, on assuming that the electrons in a chemical bond are shared equally between the atoms, neglecting theirrelative, $EN.$

$FC=V-N-\cfrac{B}{2}$       $(V=\text{no. of valance electron}\N=\text{No. of non bonding electrons}\B=\text{No. of electrons in covalent bond})$
$FC$ on $N$ in $NO^- _3=0$
$FC$ on $O$ in $NO _3^-=\cfrac{-1}{3}$

Which of the following given below is incorrect :

  1. ONF is isoelectronic with ${O _2}{N^ - }$

  2. ${\rm{O}}{{\rm{F}} _2}$ is an oxide of fluorine

  3. $C{l _2}{O _7}$ is an anhydride of perchloric acid

  4. ${O _3}$ molecule is bent


Correct Option: A