Tag: web technology

Questions Related to web technology

  1. the normal class representation with a dotted arrow pointing at the template parameter classes

  2. the normal class representation but shaded grey.

  3. the normal class representation with a dotted outline and the names of its parameter classes listed on the top right-hand corner.

  4. the normal class representation with a rectangular box in its top left-hand corner.

  5. Its a trick question - parameterized classes can't be specified in the UML notation.


Correct Option: C

XML is Case-Sensitive Language

  1. True

  2. False


Correct Option: B
  1. The before() method will print 1 2

  2. The before() method will print 1 2 3

  3. The before() method will print three numbers, but the order cannot be determined

  4. The before() method will not compile

  5. The before() method will throw an exception at runtime


Correct Option: E
  1. Change the Carnivore interface to interface Carnivore extends Hungry {}

  2. Change the Herbivore interface to interface Herbivore extends Hungry {}

  3. Change the Sheep class to class Sheep extends Animal implements Herbivore { public void munch(Grass x) {} }

  4. Change the Sheep class to class Sheep extends Plant implements Carnivore { public void munch(Wolf x) {} }

  5. Change the Wolf class to class Wolf extends Animal implements Herbivore { public void munch(Grass x) {} }

  6. No changes are necessary


Correct Option: B

Given: public static void main(String[] args) { // INSERT DECLARATION HERE for (int i = 0; i <= 10; i++) { List row = new ArrayList(); for (int j = 0; j <= 10; j++) row.add(i * j); table.add(row); } for (List row : table) System.out.println(row); } Which statements could be inserted at // INSERT DECLARATION HERE to allow this code to compile and run? (Choose all that apply.)

  1. List> table = new List>();

  2. List> table = new ArrayList>();

  3. List> table = new ArrayList>();

  4. List table = new List();

  5. List table = new ArrayList();

  6. List table = new ArrayList();


Correct Option: B
  1. "X extends Y" is correct if and only if X is a class and Y is an interface

  2. "X extends Y" is correct if and only if X is an interface and Y is a class

  3. "X extends Y" is correct if X and Y are either both classes or both interfaces

  4. "X extends Y" is correct for all combinations of X and Y being classes and/or interfaces


Correct Option: C

Given: 3. public class Wind { 4. public static void main(String[] args) { 5. foreach: 6. for(int j=0; j<5; j++) { 7. for(int k=0; k< 3; k++) { 8. System.out.print(" " + j); 9. if(j==3 && k==1) break foreach; 10. if(j==0 || j==2) break; 11. } 12. } 13. } 14. } What is the result?

  1. 0 1 2 3

  2. 1 1 1 3 3

  3. 0 1 1 1 2 3 3

  4. 1 1 1 3 3 4 4 4

  5. 0 1 1 1 2 3 3 4 4 4

  6. Compilation fails


Correct Option: C

AI Explanation

To answer this question, let's go through each option and determine if it is correct or incorrect:

Option A) 0 1 2 3 - This option is incorrect. The output does not include the number 2.

Option B) 1 1 1 3 3 - This option is incorrect. The output does not include the number 2.

Option C) 0 1 1 1 2 3 3 - This option is correct.

Explanation:

  • The outer for loop iterates from 0 to 4 (j=0,1,2,3,4).
  • The inner for loop iterates from 0 to 2 (k=0,1,2).
  • The line System.out.print(" " + j) prints the current value of j.
  • The line if(j==3 &amp;&amp; k==1) break foreach checks if j is equal to 3 and k is equal to 1. If this condition is true, the program breaks out of the outer for loop using the label "foreach".
  • The line if(j==0 || j==2) break checks if j is equal to 0 or j is equal to 2. If this condition is true, the program breaks out of the inner for loop.
  • The program prints the value of j for each iteration of the inner for loop.
  • The program stops printing when j is equal to 3 and k is equal to 1, which is why the number 2 is not printed.
  • The final output is "0 1 1 1 2 3 3".

Option D) 1 1 1 3 3 4 4 4 - This option is incorrect. The output does not include the number 0.

Option E) 0 1 1 1 2 3 3 4 4 4 - This option is incorrect. The output does not include the number 4.

Option F) Compilation fails - This option is incorrect. There are no syntax errors in the given code.

The correct answer is Option C) 0 1 1 1 2 3 3. This option is correct because it accurately represents the output of the given code.