Given: 3. class A { } 4. class B extends A { } 5. public class ComingThru { 6. static String s = "-"; 7. public static void main(String[] args) { 8. A[] aa = new A[2]; 9. B[] ba = new B[2]; 10. sifter(aa); 11. sifter(ba); 12. sifter(7); 13. System.out.println(s); 14. } 15. static void sifter(A[]... a2) { s += "1"; } 16. static void sifter(B[]... b1) { s += "2"; } 17. static void sifter(B[] b1) { s += "3"; } 18. static void sifter(Object o) { s += "4"; } 19. } What is the result?

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  1. -124

  2. -134

  3. -424

  4. -434

  5. -444

  6. Compilation fails

Show answer
Correct Option: D

AI Explanation

To answer this question, let's go through each option and see why it is correct or incorrect:

Option A) -124 - This option is incorrect because it does not match the expected output.

Option B) -134 - This option is incorrect because it does not match the expected output.

Option C) -424 - This option is incorrect because it does not match the expected output.

Option D) -434 - This option is correct.

Option E) -444 - This option is incorrect because it does not match the expected output.

Option F) Compilation fails - This option is incorrect because the code compiles successfully.

The correct answer is Option D) -434. This option is correct because the main method calls the sifter method three times with different arguments:

  1. sifter(aa) - The argument is an array of type A. The method that matches this argument is sifter(A[]... a2). Therefore, s += "1".

  2. sifter(ba) - The argument is an array of type B. The method that matches this argument is sifter(B[]... b1). Therefore, s += "2".

  3. sifter(7) - The argument is an integer. There is no method that directly matches this argument, but there is a method that can accept any object type as an argument, which is sifter(Object o). Therefore, s += "4".

Therefore, the final value of s is "-434".

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