Tag: programming languages

To answer this question, let's go through each line of code and track the values of the variables:

• int i,j,k,l=0;: This line declares four variables i, j, k, and l. l is initialized to 0.
• k = l++;: The value of l is assigned to k first, and then l is incremented by 1. So, k becomes 0, and l becomes 1.
• j = ++k;: k is incremented by 1 first, and then the value of k is assigned to j. So, k becomes 1, and j becomes 1.
• i = j++;: The value of j is assigned to i first, and then j is incremented by 1. So, i becomes 1, and j becomes 2.
• System.out.println(i);: The value of i is printed, which is 1.

Therefore, the correct answer is B) 1.

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• Wrong explanation

To answer this question, you need to understand Java modifiers.

Java modifiers are keywords that are used to specify the properties or characteristics of classes, methods, variables, and other program elements. They are used to control the visibility, accessibility, and behavior of these elements.

Let's go through each option to understand why it is correct or incorrect:

Option A) public - This option is correct. The "public" modifier is used to specify that a class, method, or variable is accessible to all other classes and code in the program.

Option B) private - This option is correct. The "private" modifier is used to specify that a class, method, or variable is only accessible within the same class.

Option C) friendly - This option is incorrect. There is no "friendly" modifier in Java. It seems like a typo or a misconception.

Option D) transient - This option is correct. The "transient" modifier is used to specify that a variable should not be serialized when an object is serialized.

The correct answer is A, B, and D. These options are correct because they are valid Java modifiers.

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• Wrong explanation