Multiple choice technology programming languages

Which option most fully describes will happen when you attempt to compile and run the following code public class MyAr{ public static void main(String argv[]) { MyAr m = new MyAr(); m.amethod(); } public void amethod(){ static int i; System.out.println(i); } }

  1. Compilation and output of the value 0

  2. Compile time error because i has not been initialized

  3. Compilation and output of null

  4. Compile time error
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Local variables cannot be declared static - only class-level fields can be static. The code 'static int i;' inside a method causes a compile-time error. Option D correctly identifies this.

AI explanation

To answer this question, let's go through each option to understand why it is correct or incorrect:

Option A) Compilation and output of the value 0 - This option is incorrect because the code will not compile.

Option B) Compile time error because i has not been initialized - This option is incorrect because the error in the code is not due to the initialization of variable i.

Option C) Compilation and output of null - This option is incorrect because the error in the code is not related to printing null.

Option D) Compile time error - This option is correct because there is a compile-time error in the code. The error occurs in the amethod() method where static int i; is declared. In Java, it is not allowed to declare local variables as static. Therefore, the code will fail to compile.

The correct answer is D. Compile time error.

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