Tag: programming languages

Questions Related to programming languages

Which is simplest and correct code snippet needs to be put in the main function to replace the value object of the HashMap for the key “orange”?

technology programming languages

  1. itemMap.remove("orange"); itemMap.put("orange", new Item("Orange") );

  2. ((Item)itemMap.get(“orange”)).name = “Orange”;

  3. itemMap.put("orange", new Item("Orange") );

  4. None of above

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Correct Option: B

Which is the most performance efficient implementation for assignCode method from the given options?
technology programming languages

  1. code attribute cannot be changed as Item class doesn’t have setter method for it.

  2. for (int i = 0; i < itemList.size(); i++) { if(itemList.get(i) != null) { ((Item)itemList.get(i)).code = 50+i; } }

  3. int i = 0; Item im = null; while (i < itemList.size()) { im = (Item)itemList.get(i); if(im != null) { im.code = 50+i; } i++; }

  4. int i = 0; Item im = null; Iterator itr = itemList.iterator(); while (itr.hasNext()) { im =(Item) itr.next(); im.code = 50+i; i++; }

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Correct Option: D

Which code from the given options if put in Main class will not print “Done”?
technology programming languages

  1. Function call:- changeName(im); Function implementation :- { im.name = "Done"; return null; }

  2. Function call:- changeName(im); Function implementation :- { im = new Item("Done"); return null; }

  3. Function call :- im = changeName(im); function implementation :- { Item otherObject = new Item("Done"); return otherObject; }

  4. All of the above

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Correct Option: B

Which is simplest code snippet you will add in the main function to set the name attribute of 50th in the ItemList to “Done”?
technology programming languages

  1. im.name = "Done";

  2. Item otherObject = new Item(“Done”); itemList.set(49, otherObject);

  3. ((Item)itemList.get(49)).name = “Done”;

  4. None of above is correct as they are not changing 50th element.

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Correct Option: A

Which of the given options code is correct and will not waste memory. Note :- Defination of the Class Item is class Item { public int code; public String name; public Item(String name) { this.name = name; } } itemList is ArrayList containing 50 objects of Class Items.

technology programming languages

  1. Item im = new Item(null); im = (Item ) itemList.get(0);

  2. Item im = new Item(“Done”); im = (Item ) itemList.get(0);

  3. Item im = null; im = (Item ) itemList.get(0);

  4. All of the above.

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Correct Option: C

Examine this package body: CREATE OR REPLACE PACKAGE BODY forward_pack IS V_sum NUMBER; - 44 - PROCEDURE calc_ord(. . . ); PROCEDURE generate_summary(. . . ) IS BEGIN Calc_ord(. . . ); . . . END calc_ord; END forward_pack; / Which construct has a forward declaration?

technology programming languages

  1. a) V_SUM

  2. b) CALC_ORD.

  3. c) FORWARD_PACK

  4. d) GENERATE_SUMMARY.

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Correct Option: B

Which of the following is not a java keyword?

technology programming languages

  1. assert

  2. interface

  3. extend

  4. transient

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Correct Option: C

AI Explanation

To answer this question, we need to understand the concept of Java keywords.

Java keywords are reserved words that have specific meanings and purposes in the Java programming language. These keywords cannot be used as identifiers (such as variable names, class names, or method names) because they are already predefined in the language.

Let's go through each option to understand why it is correct or incorrect:

Option A) assert - This option is incorrect because "assert" is a Java keyword used for assertions in the code.

Option B) interface - This option is incorrect because "interface" is a Java keyword used to define an interface, which is a collection of abstract methods.

Option C) extend - This option is correct because "extend" is not a Java keyword. "extend" is used in Java to create a subclass and inherit properties and methods from a superclass, but it is not a reserved keyword.

Option D) transient - This option is incorrect because "transient" is a Java keyword used to indicate that a variable should not be serialized during object serialization.

The correct answer is Option C) extend. This option is correct because "extend" is not a Java keyword.

which is the value of x and y after running this code? class a { public static void main(String args[]) { int x=1; int y=x++; } }
technology programming languages

  1. x=1 and y=1

  2. x=1 and y=2

  3. x=2 and y=2

  4. x=2 and y=1

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Correct Option: D

what is the value of x and y after running this code? class a { public static void main(String args[]) { int x=1; int y=x++; } }

technology programming languages

  1. x=1 and y=1

  2. x=2 and y=2

  3. x=1 and y=2

  4. x=2 and y=1

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Correct Option: D

What is the output:class a { public static void main (String args[]) { int x; int y=10; if (y>0) { x = 10; } System.out.println(x); } }

technology programming languages

  1. 10

  2. 0

  3. Garbage Value

  4. Compile time error

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Correct Option: D