Tag: programming languages

Questions Related to programming languages

What is the root level element in a hibernate mapping file?
technology programming languages

  1. a)

  2. b)

  3. c)

  4. d) None

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Correct Option: C

Which is simplest and correct code snippet needs to be put in the main function to replace the value object of the HashMap for the key “orange”?

technology programming languages

  1. itemMap.remove("orange"); itemMap.put("orange", new Item("Orange") );

  2. ((Item)itemMap.get(“orange”)).name = “Orange”;

  3. itemMap.put("orange", new Item("Orange") );

  4. None of above

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Correct Option: B

Which is the most performance efficient implementation for assignCode method from the given options?

technology programming languages

  1. code attribute cannot be changed as Item class doesn’t have setter method for it.

  2. for (int i = 0; i < itemList.size(); i++) { if(itemList.get(i) != null) { ((Item)itemList.get(i)).code = 50+i; } }

  3. int i = 0; Item im = null; while (i < itemList.size()) { im = (Item)itemList.get(i); if(im != null) { im.code = 50+i; } i++; }

  4. int i = 0; Item im = null; Iterator itr = itemList.iterator(); while (itr.hasNext()) { im =(Item) itr.next(); im.code = 50+i; i++; }

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Correct Option: D

Which of the given options code is correct and will not waste memory.

technology programming languages

  1. Item im = new Item(null); im = (Item ) itemList.get(0);

  2. Item im = new Item(“Done”); im = (Item ) itemList.get(0);

  3. Item im = null; im = (Item ) itemList.get(0);

  4. All of the above.

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Correct Option: C

Which code in the given options if put in below Main class will not print “Done”?

technology programming languages

  1. Function call:- changeName(im); Function implementation :- { im.name = "Done"; return null; }

  2. Function call:- changeName(im); Function implementation :- { im = new Item("Done"); return null; }

  3. Function call :- im = changeName(im); function implementation :- { Item otherObject = new Item("Done"); return otherObject; }

  4. All of the above

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Correct Option: B

Which code from the given options if put in Main class will not print “Done”?

technology programming languages

  1. Function call:- changeName(im); Function implementation :- { im.name = "Done"; return null; }

  2. Function call:- changeName(im); Function implementation :- { im = new Item("Done"); return null; }

  3. Function call :- im = changeName(im); function implementation :- { Item otherObject = new Item("Done"); return otherObject; }

  4. All of the above

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Correct Option: B

Which is simplest code snippet you will add in the main function to set the name attribute of 50th in the ItemList to “Done”?

technology programming languages

  1. im.name = "Done";

  2. Item otherObject = new Item(“Done”); itemList.set(49, otherObject);

  3. ((Item)itemList.get(49)).name = “Done”;

  4. None of above is correct as they are not changing 50th element.

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Correct Option: A

Which of the given options code is correct and will not waste memory. Note :- Defination of the Class Item is class Item { public int code; public String name; public Item(String name) { this.name = name; } } itemList is ArrayList containing 50 objects of Class Items.
technology programming languages

  1. Item im = new Item(null); im = (Item ) itemList.get(0);

  2. Item im = new Item(“Done”); im = (Item ) itemList.get(0);

  3. Item im = null; im = (Item ) itemList.get(0);

  4. All of the above.

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Correct Option: C

Which is simplest and correct code snippet needs to be put in the main function to replace the value object of the HashMap for the key “orange”?

technology programming languages

  1. itemMap.remove("orange"); itemMap.put("orange", new Item("Orange") );

  2. ((Item)itemMap.get(“orange”)).name = “Orange”;

  3. itemMap.put("orange", new Item("Orange") );

  4. None of above

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Correct Option: B

Which is the most performance efficient implementation for assignCode method from the given options?

technology programming languages

  1. code attribute cannot be changed as Item class doesn’t have setter method for it.

  2. for (int i = 0; i < itemList.size(); i++) { if(itemList.get(i) != null) { ((Item)itemList.get(i)).code = 50+i; } }

  3. int i = 0; Item im = null; while (i < itemList.size()) { im = (Item)itemList.get(i); if(im != null) { im.code = 50+i; } i++; }

  4. int i = 0; Item im = null; Iterator itr = itemList.iterator(); while (itr.hasNext()) { im =(Item) itr.next(); im.code = 50+i; i++; }

Show answer
Correct Option: D