Tag: programming languages

Questions Related to programming languages

Given: class Titanic { public static void main(String[] args) { Boolean bl = true; boolean b2 = false; boolean b3 = true; if((bl & b2) | (b2 & b3) & b3) System.out.print("alpha "); if((bl = false) | (b1 & b3) | (bl | b2)) System.out.print("beta "}; } } What is the result?

  1. beta

  2. alpha

  3. alpha beta

  4. Compilation fails

  5. No output is produced

  6. An exception is thrown at runtime


Correct Option: E

AI Explanation

To answer this question, let's go through each option to understand why it is correct or incorrect:

Option A) beta - This option is incorrect because the code does not reach the second if statement, which is responsible for printing "beta".

Option B) alpha - This option is incorrect because the code does not reach the first if statement, which is responsible for printing "alpha".

Option C) alpha beta - This option is incorrect because the code does not reach either of the if statements, so no output is produced.

Option D) Compilation fails - This option is incorrect because the code is syntactically correct.

Option E) No output is produced - This option is correct because neither of the if statements evaluates to true, so no output is printed.

Option F) An exception is thrown at runtime - This option is incorrect because there are no exceptions thrown in the given code.

The correct answer is E. No output is produced. This option is correct because neither of the if statements evaluates to true, so no output is printed.

  1. %macro hex(start=1, stop=10, incr=1); %local i; data null; %do i=&start to &stop by &incr; value=&i; put "Hexadecimal form of &i is " value hex6.; %end; run; %mend hex;

  2. %macro hex(start=1, stop=10, incr=1); %local i; data null; %do i=&start %to &stop %by &incr; value=&i; put "Hexadecimal form of &i is " value hex6.; %end; run; %mend hex;

  3. %macro hex(start=1, stop=10, incr=1); %local i; data null; %do i=&start to &stop by &incr; value=&i; put "Hexadecimal form of &i is " value hex6.; run; %mend hex;

  4. %macro hex(start=1, stop=10, incr=1); %local i; data null; %do i=&start to &stop by &incr; value=&i; put "Hexadeciaml form of &i is " value hex6.; %end run; %mend hex;


Correct Option: B
  1. QCMPRES: %eval(&x + &y) CMPRES: 15

  2. CMPRES: 15 QCMPRES: %eval(&x + &y)

  3. QCMPRES: 15 CMPRES: 15

  4. QCMPRES:%eval(&x+&y) CMPRES: 15


Correct Option: A
  1. TRIMN(LEFT(string))

  2. TRIM(LEFT(string))

  3. TRIMN(RIGHT(string))

  4. TRIM(RIGHT(string))


Correct Option: A
  1. Copy the contents of the Sasmacr catalog to a temporary data set.

  2. List the contents of the Sasmacr catalog as output.

  3. Copy the contents of the output window to the Sasmacr catalog.

  4. none of the above


Correct Option: B
  1. be used to assign a data set variable as a value to a macro variable.

  2. create a series of macro variables in one DATA step.

  3. automatically convert a numeric value to a character value when used to assign a value to a macro variable in a DATA step.

  4. be used to assign a numeric value to a macro variable in an SCL (SAS Component Language) program.


Correct Option: D
  1. A %MACRO statement must always be paired with a %MEND statement.

  2. A macro definition can include macro variable references, but it cannot include SAS language statements.

  3. Only macro language statements are checked for syntax errors when the macro is compiled.

  4. Compiled macros are stored in a temporary SAS catalog by default.


Correct Option: B