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Multiple choice physics reflection of light at curved surfaces the mirror formula derivation of formula for curved mirrors mirror formula and magnification

A point source of light is kept in front of a convex mirror of radius of curvature $40 cm$. The image is formed at $10 cm$ behind the mirror. Calculate the object distance

  1. 30

  2. 20

  3. 50

  4. 40
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Given: For a convex mirror, $R = -40 cm$.
$v = -10 cm$ (image is virtual).
From mirror formula, we have

$\displaystyle \frac {2}{R}=\frac {1}{u}+\frac {1}{v}$

$\displaystyle \frac {1}{u}=\frac {2}{R}-\frac {1}
{v}=\frac {2v-R}{vR}$

$\displaystyle u=\frac {vR}{2v-R}=\frac {(-10cm) \times (-40cm)}{2 \times (-10cm) - (-40cm)}$

$=+20cm$
Thus, object is placed $20 cm$ in front of the mirror.

Multiple choice physics reflection of light at curved surfaces the mirror formula derivation of formula for curved mirrors mirror formula and magnification

Mirror formula is valid for:

  1. Convex mirror

  2. Concave mirror

  3. Both A and B

  4. For lenses and mirrors
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation
Mirror formula is:
$\dfrac {1}{v} + \dfrac {1}{u} = \dfrac {1}{f}$
That is; $\dfrac {1}{\text {Object Distance}} + \dfrac {1}{\text {Image Distance}} = \dfrac {1}{\text {Focal length of the mirror}}$
This relationship is applicable for both concave and convex mirrors.
Multiple choice physics reflection of light at curved surfaces the mirror formula derivation of formula for curved mirrors mirror formula and magnification

Mirror formula can also be written as:

  1. $\dfrac {1}{2v} + \dfrac {1}{2u} = \dfrac {1}{2f}$

  2. $\dfrac {1}{v} + \dfrac {1}{u} = \dfrac {2}{R}$

  3. $\dfrac {1}{v} + \dfrac {2}{u} = \dfrac {1}{f}$

  4. $\dfrac {1}{2v} + \dfrac {4}{u} = \dfrac {3}{R}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Focal length, $f = \dfrac {R}{2}$, where $R$ = radius of curvature

So, $\dfrac {1}{v} + \dfrac {1}{u} = \dfrac {1}{f}$ can be written as
$\Rightarrow \dfrac {1}{v} + \dfrac {1}{u} = \dfrac {2}{R}$

Multiple choice physics reflection of light at curved surfaces the mirror formula derivation of formula for curved mirrors mirror formula and magnification

Mark the incorrect statement regarding mirror formula.

  1. Values of known and unknown parameters can be used with their proper signs

  2. Sign of unknown parameter comes of its own after calculation

  3. Mirror formula is applicable for both concave and convex mirrors

  4. All
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The values of known parameter should be used with their proper sign convention. No sign should be attached to the unknown parameter during calculation. Its sign will come of its own after calculation.

Multiple choice physics reflection of light at curved surfaces the mirror formula derivation of formula for curved mirrors mirror formula and magnification

The relation among u, v and f for a mirror is

  1. $f = uv/(u+v)$

  2. $v = fu/(u+f)$

  3. $u = fv/(f+v)$

  4. All of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

According to mirror equation.

$\cfrac{1}{f} = \cfrac{1}{u}+ \cfrac{1}{v}$
$\cfrac{1}{f} = \cfrac{u+v}{uv}$
$f = \cfrac{uv}{u+v}$

Similarly,
$v = \cfrac{fu}{u-f}$
$u = \cfrac{fv}{v-f}$

Multiple choice physics reflection of light at curved surfaces the mirror formula derivation of formula for curved mirrors mirror formula and magnification

The relation among $u,v$ and $f$ for a mirror is:

  1. $f=uv(u+v)$

  2. $v=fu(u+f)$

  3. $u=fv(f+v)$

  4. None of these
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

from mirror formula

              $\dfrac { 1 }{ v } +\dfrac { 1 }{ u } =\dfrac { 1 }{ f } $
              $\Rightarrow \quad \boxed { f=\dfrac { uv }{ u+v }  } $
and
          $1+\dfrac { v }{ u } =\dfrac { v }{ f } \Rightarrow \boxed { u=\dfrac { fv }{ f-v }  } $

Multiple choice physics electric current through conductors study about cells electric cell types of cells

What is the $-$ve terminal of dry cell made up of?

  1. Carbon rod

  2. Zinc plate

  3. Magnesium plate

  4. Cadmium rod
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation
The dry cell consists of a zinc can, electrolyte paste, and a carbon rod in the center. A chemical reaction takes place between the zinc can and the paste. Electrons flow from the negative (zinc) terminal to the positive (carbon) terminal. Electrons are then pumped back to the negative terminal.
Multiple choice physics electric current through conductors study about cells electric cell types of cells

In secondary cells:

  1. Chemical changes can be reversed by heating electrodes

  2. Chemical changes can be reversed by passing electric current

  3. Current is produced by photo chemical reactions

  4. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Answer is B.

When a primary cell is used, chemical reactions in the battery use up the chemicals that generate the power; when they are gone, the battery stops producing electricity and is useless. In contrast, in a secondary cell, the reaction can be reversed by running a current into the cell with a battery charger to recharge it, regenerating the chemical reactants.