Tag: technology

Quizzes (307) Questions (36705)

Questions Related to technology

Multiple choice technology security

Which line of the code should be deleted to remove vulnerability? int main(int argc,char* argv[]) { int ptr1=new int; if(ptr1==NULL) exit(1); int *ptr2=new int; if(ptr2==NULL) exit(1); char j; j=argv[1]; int k=atoi(j); if (j==0){ Ptr1=&k; delete ptr2; /1/ } else { Ptr2=&k; } delete ptr1; /2/ delete ptr2; /3/ return 0; }

  1. delete ptr2; (within if loop) AND delete ptr1;

  2. delete ptr1; AND delete ptr2; (outside if loop )

  3. delete ptr2; (within if loop)

  4. delete ptr2; (outside if loop )
Reveal answer Fill a bubble to check yourself
C Correct answer
Full explanation
Multiple choice technology security

Will following program execute successfully ? int main(int argc,char* argv[]){ int *ptr=new int; if(ptr==NULL) exit(1); char *j; for(int i=1;i<=4;i++) { j=argv[i]; int k=atoi(j); if (k!=0){ *ptr=k; delete ptr; } } }

  1. Program works when there is only 1 argument with program

  2. Program works when there are 3 arguments with program

  3. Program works when there are 4 arguments with program

  4. Program never executes successfully
Reveal answer Fill a bubble to check yourself
D Correct answer
Full explanation
Multiple choice technology security

With the size of unsigned integers being 4 bytes, What happens when a negative number is entered? unsigned int i; scanf("%u",&i);

  1. A run-time error is encountered and the program aborts

  2. unsigned int variables cannot store the sign (+ or -) of the number. The sign is discarded and only the number is stored in i

  3. A large positive number will be stored in i

  4. Unsigned int variables cannot store signed numbers. Hence in this program i will contain garbage values.
Reveal answer Fill a bubble to check yourself
C Correct answer
Full explanation
Multiple choice technology security

What can go wrong in following code? #include int main(int argc, char *argv[]){ if(argc != 3){ printf("usage: %s [source] [dest]\n", argv[0]); exit(1); } char buffer1[5]; strcpy(buffer1, argv[1]); char buffer2[5]; strcpy(buffer1, argv[1]); char x; FILE *file[2]; file[0] = fopen(buffer1,"r+"); file[1] = fopen(buffer2,"w+"); for(x = 0; x < 2; x++){ if(file[x] == NULL){ printf("error opening file.\n"); exit(1); } } do { x = fgetc(file[0]); fputc(x,file[1]); } while(x != EOF); for(x = 0; x < 2; x++) fclose(file[x]); return 0; }

  1. XSS

  2. Arc Injection

  3. Buffer Overflow

  4. Arc Injection AND Buffer Overflow
Reveal answer Fill a bubble to check yourself
D Correct answer
Full explanation