Tag: biology

Questions Related to biology

PS I has

  1. More chlorophylls and more accessory pigments

  2. More chlorophylls and less accessory pigments

  3. Less chlorophylls and more accessory pigments

  4. Less chlorophylls and less accessory photosynthetic pigments


Correct Option: A
Explanation:

Photosystem I is one of the two membrane-bound photosystems of plants, algae and cyanobacteria that facilitate light-determined electron transport from water to NADPH. It utilizes absorbed light for electron transport from plastocyanin on the lumenal side to ferredoxin on the stromal side of the thylakoid membrane. In plants, this special integral membrane complex consists of more than 15 protein subunits, approximately 175 chlorophyll molecules, 2 phylloquinones and 3 Fe$ _4$S$ _4$ clusters. Whereas Photosystem II (of cyanobacteria and green plants) is as many as 35 chlorophyll a, 12 beta-carotene, two pheophytins, two plastoquinone, two heme, one bicarbonate, 20 lipid molecules and other ionic clusters. Thus Photosystem I contains more chlorophylls and accessory pigments.

DCMU inhibits

  1. PS II

  2. PS I

  3. Destroys chloroplast

  4. Inhibits oxidative phosphorylation


Correct Option: A
Explanation:

DCMU or Dichlorophenyl dimethyl urea inhibits PS II in photosynthetic plants by blocking electron transfer from plastoquinone to cytochrome. DCMU binds to and blocks the site of plastoquinone, thus hinders the path and growth of plants. It is used as herbicide and algicide. It is also used in studying photosynthetic activity.

Photosynthesis II is concerned with

  1. Photolysis of water

  2. Flowering

  3. Reduction of CO$ _2$

  4. Release of energy


Correct Option: A
Explanation:

Being a light reaction, non-cyclic photophosphorylation occurs in the thylakoid membrane. First, a water molecule is broken down into 2H+ + 1/2 O2 + 2e by a process called photolysis (or light-splitting). The two electrons from the water molecule are kept in photosystem II, while the 2H+and 1/2O2 are left out for further use. Then a photon is absorbed by chlorophyll pigments surrounding the reaction core center of the photosystem. The light excites the electrons of each pigment, causing a chain reaction that eventually transfers energy to the core of photosystem II, exciting the two electrons that are transferred to the primary electron acceptor, pheophytin. The deficit of electrons is replenished by taking electrons from another molecule of water. 


So, the correct option is 'Option A'.

PS I is inactive at

  1. 550 nm

  2. 680 nm

  3. 690 nm

  4. 780 nm


Correct Option: D
Explanation:

A) PS I can funtion at wavelengths of 700 nm or less. So, it will be active at 550 nm. But its maximum activity is at 700 nm.
B) It will be active at 680 nm.
C) It will be active at 690 nm.

D) PS I cannot function at wavelengths greater than 700 nm.
So the correct answer is '780 nm'.

A photosystem Contains

  1. pigments, a reaction centre, and an electron acceptor

  2. ADP1 P1 and hydrogen ions $(H^+)$

  3. protons, photons and pigments

  4. both (b) and (C)


Correct Option: A
Explanation:

Photosystems refer to PSI and PSII. Photosystem II contains chlorophyll a, as well as up to 50% chlorophyll b. It probably evolved later as a supplement to Photo I. It is needed to capture enough energy to do the biosynthetic reactions of the dark reaction. Its reaction centre is a molecule called P680 which absorbs light maximally at 680 nm. Similarly, PSI or P700 absorbs light at 700nm. A reaction centre comprises several (>10 or >11) protein subunits, that provide a scaffold for a series of cofactors. The cofactors can be pigments (like chlorophyllpheophytin, carotenoids), quinones, or iron-sulfur clusters and electron acceptors for transduction in the electron transport chain. 

So, the correct option is, 'pigments, a reaction centre, and an electron acceptor'.

The active component of photosystem-I composed of

  1. chlorophyll-a with absorption peak at 680 nm

  2. chlorophyll-a with absorption peak at 700 nm

  3. chlorophyll-b with absorption peak at 680 nm

  4. chlorophyll-a chlorophyll-b with absorption peak at 700 nm


Correct Option: B
Explanation:
The reaction center of photosystem-I is composed of two chlorophyll molecules and is therefore referred to as a dimer. The dimer is composed of one chlorophyll a molecule and one chlorophyll a' molecule with absorption peak at 700 nm.
Thus, the correct answer is 'chlorophyll a with absorption peak at 700 nm.'

Mature ovary forms the

  1. Seed

  2. Stamen

  3. Pistil

  4. Fruit


Correct Option: D
Explanation:

Fruits are formed by the maturation of one or more ovary. Fruits contain seeds resulting from the maturation of fertilized ovules. However, maturation of seed and fruit can occur in the absence of fertilization. In fleshy fruits, the outer covering is called as pericarp. Pericarp is again made of three layers, the epicarp, which is the outermost layer; the mesocarp, which is the middle layer; and the endocarp, which is the inner layer surrounding the ovary or the seeds. 

So, the correct answer is option D.

Which of the following is a post fertilisation event in flowering plants?

  1. Transfer of pollen grains

  2. Embryo development

  3. Formation of flower

  4. Formation of pollen grains


Correct Option: B
Explanation:
Events in sexual reproduction after the fertilisation are called post-fertilisation events. After fertilisation, a diploid zygote is formed in all sexually reproducing organisms. The process of development of embryo from the zygote is called embryogenesis.
So, the correct answer is 'Embryo development'.

In angiosperms, normally after fertilisation.

  1. The zygote divides earlier than the primary endosperm nucleus

  2. The primary endosperm nucleus divides earlier than the zygote

  3. Both the zygote and primary endosperm nuclei divide simultaneously

  4. Both the zygote and primary endosperm nuclei undergo a resting period


Correct Option: B
Explanation:

Endosperm is the nutritive tissue for the developing embryo and the seedlings. In angiosperm, the endosperm develops from triploid primary endosperm nucleus which is formed as a result of vegetative fertilization, triple fusion or fusion of male gamete with the secondary nucleus of the central cell. Generally, endosperm divides before zygote because it will provide nourishment to the developing zygote.

So, the correct option is 'The primary endosperm nucleus divides earlier than the zygote'

In angiosperms, triple fusion is required for formation of

  1. Embryo

  2. Endosperm

  3. Suspensor

  4. Fruit wall


Correct Option: B
Explanation:
Angiosperms have a unique phenomenon of double fertilisation in which after the release of two male gametes inside the embryo sac by the pollen tube, one male gamete (first male gamete which is closest to the egg) fuses with egg nucleus and this phenomenon is known as fertilisation or syngamy and results in the formation of zygote.
The other male gamete i.e. the second male gamete migrates towards the secondary nucleus (formed from fusion of two polar nuclei) and fuses with it. This phenomenon is known as triple fusion and results in the formation of a triploid primary endosperm mother cell. Primary endosperm mother cell then undergoes further divisions to form endosperm. Hence, triple fusion is required for the formation of endosperm.
So, the correct answer is B.