Tag: mutual inductance

Questions Related to mutual inductance

A $50\ Hz$ ac current of peak value $2$ A flows through one of the pair of coils. If the mutual inductance between the pair of coils is $150\ mH$. then the peak value of voltage induced in the second coil is

  1. $30\pi\ V$

  2. $60\pi\ V$

  3. $15\pi\ V$

  4. $300\pi\ V$

  5. $3\pi\ V$


Correct Option: A
Explanation:

Let the current flows through coil 1 is, ${{I} _{1}}={{I} _{0}}\sin \omega t$ where, ${{I} _{0}}$is peak value of current.

Magnetic flux linked with coil 2 is ${{\phi } _{2}}=M   {{I} _{1}}=M{{I} _{0}}\sin \omega t$

Emf in coil 2 is

${{\varepsilon } _{2}}=\dfrac{d{{\phi } _{2}}}{dt}=\dfrac{d(M{{I} _{0}}\sin \omega t)}{dt}=M \omega {{I} _{0}}\cos \omega t$

So, peak value of voltage induced in coil 2 is $=M{{I} _{o}}\omega ....(1)$

Given that,

$ \nu =50\,Hz $

$ {{I} _{0}}=2\,A $

$ L=150\,mH $

$ \omega =2\pi \nu =2\pi \times 50 $

Put all values in equation (1)

$ current=150\times {{10}^{-3}}\times 2\times 100\pi  $

$ I=30\pi \,V $

The self-inductances of two identical coils are $0.1\ H$. They are wound over each other. Mutual inductance will be-

  1. $0.1\ H$

  2. $0.2\ H$

  3. $0.01\ H$

  4. $0.05\ H$


Correct Option: A

The length of solenoid is 0.3 m and the number of turns is 2000. The area of cross-section of the solenoid is $1.2\times 10^{-3} m^2$. Another coil of turns 200 is wrapped over the solenoid. a current of 2 A is passed through the solenoid and its direction is changed in 0.25 sec. Then the induced emf in the coil:

  1. $4.8\times10^{-2} V$

  2. $4.8\times10^{-3} V$

  3. $3.2\times10^{-3} V$

  4. $3.2\times10^{-2} V$


Correct Option: A
Explanation:
$N _1=2000$
$N _2=300$
$A=1.2\times 10^{-3}m^2$
$l=0.3\ m$
$t=0.25\ s$
$I=0.2\ A$
we know,

Mutual inductance $(M)=\dfrac{\mu _0N _1N _2A}{l}$

$\Rightarrow M=\dfrac{\mu _0N _1N _2A}{l}$

also,
induced emf $(\varepsilon)=M.\dfrac{dI}{dt}$

and $\dfrac{dI}{dt}=\dfrac{2-(-2)}{0.25}=\dfrac{4}{0.25}=16$

so $\varepsilon =M\dfrac{dI}{dt}=\dfrac{\mu _0N _1N _2A}{l}.\dfrac{dI}{dt}$

$\varepsilon=\dfrac{4\pi \times 10^{-7}\times 2000\times 300\times 1.2\times 10^{-3}\times 16}{0.3}$

$\boxed{\varepsilon=0.048\ V=4.8\times 10^{-2}\ V}$ hence $(A)$ option is correct

A coil of radius $1\ cm$ and of turns $100$ is placed in the middle of a long solenoid of radius $5\ cm$ and having $5\ turns/ cm$. The mutual induction in millihenry is

  1. $0.0316$

  2. $0.063$

  3. $0.105$

  4. Zero


Correct Option: A

When 100 volts d.c. is applied across solenoid a current of 1.0 amp flows in it. When 100 volts a.c. is applied across the same coil, the current drops to 0.5 amp. If the frequency of the a.c. source is 50 Hz the impedance and inductance of the solenoid are

  1. 200 ohm and 0.55 Henry

  2. 100 ohm and 0.86 Henry

  3. 200 ohm and 1.0 Henry

  4. 100 ohm and 0.93 Henry


Correct Option: A

The inductance of a solenoid 0.5 m long of cross-sectional area $420 cm^{2}$ and with $500$ turns is 

  1. $12.5\ mH$

  2. $1.25\ mH$

  3. $15.0\ mH$

  4. $0.12\ mH$


Correct Option: B

A current I flows in an infinity long wire with cross section in the from of a semicircular ring of radius R the magnitude of the magnetic induction along its axis is :- 

  1. $\dfrac { \mu _ { 0 } I } { 2 \pi R }$

  2. $\dfrac { \mu _ { 0 } \mathbf { I } } { 4 \pi R }$

  3. $\dfrac { \mu _ { 0 } I } { \pi ^ { 2 } R }$

  4. $\dfrac { \mu _ { 0 } I } { 2 \pi ^ { 2 } R }$


Correct Option: C
Explanation:

Let semicircular ring of radius $R$ as shown in figure 

An elementary length $dl$ cut for finding magnetic field,
So, 
$dl = Rd\theta $
So, elementary current along $dl$ is $di = \frac{i}{{\pi R}} \times Rd\theta  = \frac{{id\theta }}{\pi }$.
Now, you can see that elementary part of length is perpendicular upon $dB$.
so,
$dB = \frac{{{\mu _0}di}}{{2\pi R}}$

$ = \frac{{{\mu _0}di}}{{2{\pi ^2}R}}$


Now, magnetic filed along axis $B = \int\limits _0^\pi  {db.\sin \theta d\theta }  = 2dB$
Now, put $dB$ in here,
So, $B = \frac{{{\mu _o}i}}{{{\pi ^2}R}}$
Hence, 
Option $C$ is the correct answer.

What is inductance of a 25 cm long solenoid if it has 1000 turns an radius of its circular cross-section is 5 cm ?

  1. 0.04 H

  2. 0.02 H

  3. 0.8 H

  4. 0.1 H


Correct Option: B

A coil of mean area 500 $cm^2$ and having 1000 turns is held perpendicular to a uniform field of 0.4 gauss. The coil is turned through $180^o$ in $\frac{1}{10}$second. The average induced e.m.f. :-

  1. $0.04 V$

  2. $0.4 V$

  3. $4 V$

  4. $0.004 V$


Correct Option: A

The M.I. of a disc  about its diameter is $2$ units. Its M.I. about axis through a point on its rim in the plane of the disc is

  1. $4$ units

  2. $6$ units

  3. $8$ units

  4. $10$ units


Correct Option: A