Tag: effect of temperature and pressure on states of matter

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Multiple choice chemistry matter around us measurement of properties effect of temperature and pressure on states of matter general introduction: importance and scope of chemistry

If $T _1$ and $T _2$ are two temperatures, which of the following expressions will yield the same value whether both temperatures are given in Celsius or Kelvin?

  1. $T _1+T _2$
  2. $T _1-T _2$
  3. $T _1\times T _2$
  4. $\dfrac{T _1}{T _2}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Temperature differences are the same in both Celsius and Kelvin scales because the size of one degree Celsius is equal to the size of one Kelvin. Thus, T1 - T2 remains constant regardless of the scale used.

Multiple choice chemistry matter around us measurement of properties effect of temperature and pressure on states of matter general introduction: importance and scope of chemistry

Which of the following is the correct value of $R$ in $SI$ units?

  1. $0.083$ $bar$ $dm^{3}K^{-1}mol^{-1}$
  2. $1.98\ cal K^{-1}mol^{-1}$
  3. $8.314\times 10^{7} erg K^{-1}mol^{-1}$
  4. $8.314 J\ K^{-1}mol^{-1}$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

$R$ is called as universal gas constant or molar gas constant.

              $R=0.0821\quad L\quad atm\quad { mol }^{ -1 }{ k }^{ -1 }\ R=0.0831\quad { dm }^{ 3 }bar\quad { mol }^{ -1 }{ k }^{ -1 }\ R=8.314\quad J\quad { mol }^{ -1 }{ k }^{ -1 }\ R=8.314\times { 10 }^{ 7 }erg\quad { mol }^{ -1 }{ k }^{ -1 }\ R=1.98\quad Cal\quad { mol }^{ -1 }{ k }^{ -1 }$
The $S.I$ units of molar gas constant $(R)$ is $J\quad { mol }^{ -1 }{ k }^{ -1 }$.
$\therefore \quad R=8.314\quad J\quad { mol }^{ -1 }{ k }^{ -1 }$ is the correct answer.

Multiple choice chemistry matter around us measurement of properties effect of temperature and pressure on states of matter general introduction: importance and scope of chemistry

$1^{\circ}C$ rise in temperature is equal to rise of:

  1. ${ 1 }^{ 0 }F$
  2. ${ 9/5 }^{ 0 }F$
  3. ${ 5/9 }^{ 0 }F$
  4. ${ 33 }^{ 0 }F$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solution:- (B) $\cfrac{9}{5} ℉$

As we now that,
$F  = \cfrac{9}{5} C + 32$
As the temperature is risen by $1 ℃$-
$C' = C + 1$
Therefore,
$F' = \cfrac{9}{5} \left( C + 1 \right) + 32$
$F' = \cfrac{9}{5}C + \cfrac{9}{5} + 32$
$\Rightarrow F' = \left( \cfrac{9}{5}C + 32 \right) + \cfrac{9}{5}$
$\Rightarrow F' = F + \cfrac{9}{5}$
Hence $1 ℃$ rise in temperature is equal to the rise in $\cfrac{9}{5} ℉$.