Tag: effect of temperature and pressure on states of matter

Questions Related to effect of temperature and pressure on states of matter

Atomic radius is expressed in the _______ units.

  1. angstrom

  2. cm

  3. m

  4. nm


Correct Option: A
Explanation:

Atomic radius is usually expressed in Angstrom units. It is because the size of atom is very small. It is equivalent to $1\times {10}^{-10}$metres.

Weight of diamonds are measured in________.

  1. aunce

  2. Kg

  3. carats

  4. pounds


Correct Option: C
Explanation:

One carat is equal to exactly $0.2$ grams.

The word 'carat' came from the "carob" seed, which was used by diamond traders as the original unit.

If $T _1$ and $T _2$ are two temperatures, which of the following expressions will yield the same value whether both temperatures are given in Celsius or Kelvin?

  1. $T _1+T _2$

  2. $T _1-T _2$

  3. $T _1\times T _2$

  4. $\dfrac{T _1}{T _2}$


Correct Option: B

Which of the following has the highest numeric value?

  1. $100$ Tm

  2. $1000$ Gm

  3. $10^4$ mm

  4. $10^6$ nm


Correct Option: A
Explanation:

$100\ Tm=100000\ Gm$

$1000\ Gm$
$10^4\ mm=1\times10^{-10}\ Gm$
$10^6\ nm=1\times10^{-12}\ Gm$

Which of the following is the correct value of $R$ in $SI$ units?

  1. $0.083$ $bar$ $dm^{3}K^{-1}mol^{-1}$

  2. $1.98\ cal K^{-1}mol^{-1}$

  3. $8.314\times 10^{7} erg K^{-1}mol^{-1}$

  4. $8.314 J\ K^{-1}mol^{-1}$


Correct Option: D
Explanation:

$R$ is called as universal gas constant or molar gas constant.

              $R=0.0821\quad L\quad atm\quad { mol }^{ -1 }{ k }^{ -1 }\ R=0.0831\quad { dm }^{ 3 }bar\quad { mol }^{ -1 }{ k }^{ -1 }\ R=8.314\quad J\quad { mol }^{ -1 }{ k }^{ -1 }\ R=8.314\times { 10 }^{ 7 }erg\quad { mol }^{ -1 }{ k }^{ -1 }\ R=1.98\quad Cal\quad { mol }^{ -1 }{ k }^{ -1 }$
The $S.I$ units of molar gas constant $(R)$ is $J\quad { mol }^{ -1 }{ k }^{ -1 }$.
$\therefore \quad R=8.314\quad J\quad { mol }^{ -1 }{ k }^{ -1 }$ is the correct answer.

The prefix zepto stands for:

[Note : unit in m]

  1. $10^9$

  2. $10^{-12}$

  3. $10^{-15}$

  4. $10^ {-21}$


Correct Option: D
Explanation:

Zepto = $10^{-21}m$ .

$1^{\circ}C$ rise in temperature is equal to rise of:

  1. ${ 1 }^{ 0 }F$

  2. ${ 9/5 }^{ 0 }F$

  3. ${ 5/9 }^{ 0 }F$

  4. ${ 33 }^{ 0 }F$


Correct Option: B
Explanation:

Solution:- (B) $\cfrac{9}{5} ℉$

As we now that,
$F  = \cfrac{9}{5} C + 32$
As the temperature is risen by $1 ℃$-
$C' = C + 1$
Therefore,
$F' = \cfrac{9}{5} \left( C + 1 \right) + 32$
$F' = \cfrac{9}{5}C + \cfrac{9}{5} + 32$
$\Rightarrow F' = \left( \cfrac{9}{5}C + 32 \right) + \cfrac{9}{5}$
$\Rightarrow F' = F + \cfrac{9}{5}$
Hence $1 ℃$ rise in temperature is equal to the rise in $\cfrac{9}{5} ℉$.