Tag: speed and acceleration of travelling wave

Questions Related to speed and acceleration of travelling wave

Multiple choice physics wave motion wave velocity speed and acceleration of travelling wave speed of a travelling wave

A transverse wave on a string has an amplitude of $02m$ and a frequency of $175Hz$. Consider a particle of the string at $x=0$. It begins with a displacement $y=0$ at $t=0$, according to equation $y=0.2\sin{(kx+\omega t)}$. How much time passes between the first two instant when this particle has a displacement of $y=0.1m$>

  1. $1.9ms$

  2. $3.9ms$

  3. $2.4ms$

  4. $0.5ms$

Reveal answer Fill a bubble to check yourself
C Correct answer
Multiple choice physics wave motion wave velocity speed and acceleration of travelling wave speed of a travelling wave

For a string clamped at both its ends, which of the following wave equation is/are valid for a stationary wave set up in it? (Origin is at one end of string).

  1. $y=A\sin kx.\sin \omega t$

  2. $y=A\cos kx \sin \omega t$

  3. $y=A\sin kx. \cos \omega t$

  4. $y=A\cos kx \cos \omega t$

Reveal answer Fill a bubble to check yourself
A,C Correct answer
Explanation

For all values of t, y$=0$ at $x=0$
Hence, (A) and (C) are correct.

Multiple choice physics wave motion wave velocity speed and acceleration of travelling wave speed of a travelling wave

A certain strings will resonate to several frequencies , the lowest of which is $200$cps.what are the next three higher frequencies to which it resonates? 

  1. $400,600,800$

  2. $300,400,500$

  3. $100,150,200$

  4. $200,250,300$

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
Given,  The Lowest frequency is $200cps$

Let  $f$ resonant the fundamental frequency, then the next higher frequency is: $2f,3f,4f$

$2\times200=400cps,3\times200=600,4\times200=800cps$


Multiple choice physics wave motion wave velocity speed and acceleration of travelling wave speed of a travelling wave

A wire stretched between two rigid supports vibrates in its fundamental mode with a frequency of $45 Hz$. The mass of the wire is $3.5 \times 10^{-2}kg$ and its linear mass density is $4.0 \times 10^{-2} kgm^{-1}$. What is the speed of a transverse wave on the wire?

  1. $69 \ ms^{-1}$

  2. $79 \ ms^{-1}$

  3. $89 \ ms^{-1}$

  4. $99 \ ms^{-1}$

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

For a wire vibrating in its fundamental mode, the frequency f = v / (2L). However, we can use the relation v = sqrt(T/mu). Given the mass M = 0.035 kg and linear density mu = 0.04 kg/m, the length L = M/mu = 0.875 m. The fundamental frequency f = v / (2L) = 45 Hz, so v = 45 * 2 * 0.875 = 78.75 m/s, which rounds to 79 m/s.

Multiple choice physics wave motion wave velocity speed and acceleration of travelling wave speed of a travelling wave

A person observe two points on a string as a travelling wave passes them. The points are at $x _ { 1 } = 0$ and $x _2 = 1m$. The transverse motions of the two points are found to be as follows: $y _ { 1 } = 0.2 \sin 3 \pi t$
$y _ { 2 } = 0.2 \sin ( 3 \pi t + \pi/8 )$ What is the frequency in Hertz?

  1. $1.5 Hz$

  2. $3 Hz$

  3. $4.5 Hz$

  4. $1 Hz$

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The transverse motion is given by y = A sin(omega * t + phi). Comparing y1 = 0.2 sin(3 * pi * t) with the standard form, omega = 3 * pi. Since omega = 2 * pi * f, we have 3 * pi = 2 * pi * f, which gives f = 1.5 Hz.

Multiple choice physics wave motion wave velocity speed and acceleration of travelling wave speed of a travelling wave

If $n,2n,3n$ are the fundamental frequencies of the three segments into which a string is divided by placing required number of bridges below it. If $n _0$ is the fundamental frequency of the string, then 

  1. $n _0=3n$

  2. $n _0=6n$

  3. $n _0=\dfrac{3n}{5}$

  4. $n _0=\dfrac{6n}{11}$

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The fundamental frequency of a string is f = v / (2L). When divided into segments of lengths L1, L2, L3, the frequencies are f1 = v / (2L1) = n, f2 = v / (2L2) = 2n, f3 = v / (2L3) = 3n. The total length L = L1 + L2 + L3 = v/(2n) + v/(4n) + v/(6n) = (6+3+2)v / 12n = 11v / 12n. The fundamental frequency of the whole string is f0 = v / (2L) = v / (2 * 11v / 12n) = 6n / 11.

Multiple choice physics wave motion wave velocity speed and acceleration of travelling wave speed of a travelling wave

A spring of force constant K is first stretched by distance a from its natural length and then future by distance b. The work done in stretching the part b is

  1. $\dfrac{1}{2}$Ka(a-b)

  2. $\dfrac{1}{2}$Ka(a+b)

  3. $\dfrac{1}{2}$Kb(a-b)

  4. $\dfrac{1}{2}$Kb(2a+b)

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Work done by spring in its natural length$=\cfrac{1}{2} \times k \times x^{2}= \cfrac{1}{2} \times k \times a^{2}$

So, total work$=\cfrac{1}{2}k(a+b)^{2}$
for work done for stretching 'b'
$\cfrac { 1 }{ 2 } \times k\times (a+b)^{ 2 }-\cfrac { 1 }{ 2 } \times k\times a^{ 2 }=\cfrac { 1 }{ 2 } \times k\times b\times (2a+b)$