Tag: introduction to interest

Questions Related to introduction to interest

If the interest on $1700$ rupees is $340$ rupees for $2$ year the rate of interest must be

  1. $12\ \%$

  2. $15\ \%$

  3. $4\ \%$

  4. $10\ \%$


Correct Option: D
Explanation:

Principle$=Rs1770\quad\quad Time=2years$

$SI=Rs340\quad\quad Rate=?\ \cfrac{P\times R\times T}{100}=340\Rightarrow \cfrac{1770\times R\times 2}{100}=340\ \Rightarrow R=\cfrac{340\times100}{1770\times2}=\cfrac{340\times5}{177}=9.6\%$

The simple interest on a sum money is 4/9 of the principal and the number of years is equal to the rate percent per annum. The rate per annum is :  

  1. $5$%

  2. $6\dfrac{2}{3}\%$

  3. $6$%

  4. $7\dfrac{1}{5}\%$


Correct Option: B
Explanation:
Let the principal be $P$.
Rate of interest be $R\%$
According to the question, Time$=R$
Simple interest $=\dfrac{4P}{9}$.
$SI =\dfrac{\left(PTR\right)}{100}$
$\Rightarrow \dfrac{4P}{9} =\dfrac{\left(PTR\right)}{100}$
$\Rightarrow \dfrac{4P}{9} =\dfrac{\left(P\times R\times R\right)}{100}$
$\Rightarrow \dfrac{4P}{9} =\dfrac{\left(P\times {R}^{2}\right)}{100}$
$\Rightarrow \dfrac{4}{9} =\dfrac{{R}^{2}}{100}$
$\Rightarrow {R}^{2}=100\times\dfrac{4}{9}$
$\Rightarrow R= 10\times \dfrac{2}{3}=\dfrac{20}{3}$
Therefore, rate of interest is $\dfrac{20}{3}\%$ or  $6\dfrac{2}{3}\%$.

A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is :

  1. Rs. 650

  2. Rs. 690

  3. Rs. 698

  4. Rs. 700

  5. Rs. 715


Correct Option: C
Explanation:

S.I. for $1$ year $= Rs. (854-815) = Rs. 39$


S.I. for $3$ years = Rs. $39 \times 3=Rs. 117$


Therefore,

Principal $= Rs. 815 - Rs. 117 = Rs. 698$

A four year Indira Vikas certificate with a maturity value of Rs. 700 is purcahsed for Rs. 500. The rate $\%$ p.a. is :

  1. $

    9 \dfrac { 1 } { 11 } \%

    $

  2. $10\%$

  3. $11\%$

  4. $

    21 \dfrac { 9 } { 11 } \%

    $


Correct Option: B
Explanation:

Interest $= 200.....(700-500=200)$


$SI=\dfrac{P\times N\times R}{100}$

$200=\dfrac{500 \times R \times 4}{100}\implies R=10\%$

At what rate per cent per annum, will Rs.32000 yield a compound interest of Rs.5044 in 9 months interest being compounded quarterly ?

  1. 25

  2. 23

  3. 20

  4. 18


Correct Option: C
Explanation:
Principal = Rs.32000 
Amount $= Rs.(32000 + 5044) = Rs.37044$
Rate $= r\%$ p.a. or $\displaystyle \cfrac{r}{4}\%$ per quarter 
Time = 9 months = 3 quarters i.e., $n = 3$
$\displaystyle \therefore$ Applying $\displaystyle A=P\left ( 1+\cfrac{r}{100} \right )^{n}$ we have
$\displaystyle 37044=32000\left ( 1+\cfrac{r}{400} \right )^{3}\Rightarrow \cfrac{37044}{32000}=\left ( 1+\cfrac{r}{400} \right )^{3}$
$\displaystyle \Rightarrow \cfrac{9261}{8000}=\left ( 1+\cfrac{r}{400} \right )^{3}\Rightarrow \left ( \cfrac{21}{20} \right )^{3}=\left ( 1+\cfrac{r}{400} \right )^{3}$
$\displaystyle \Rightarrow 1+\cfrac{r}{400}=\cfrac{21}{20}\Rightarrow \cfrac{r}{400}=\cfrac{21}{20}-1=\cfrac{1}{20}\Rightarrow r=\cfrac{400}{20}=20\%p.a.$

At what rate of interest per annum will a sum double itself in 8 years?

  1. $25\%$

  2. $6\frac{1}{4} \%$

  3. $12\frac{1}{2} \%$

  4. None


Correct Option: C
Explanation:

T = 8 years; N = 2; R = ?
R $\times T$ = 100 $\times (N - 1)$


R $\times 8$= 100 $\times (2 - 1)$

$R\, =\, \displaystyle \frac {100}{8}\, =\, 12\frac{1}{2}\, \%$

Simple interest on Rs.2000 for 4 years is Rs.400. Percent rate of interest is

  1. $\displaystyle\frac{2000\times 100}{400\times 4}$

  2. $\displaystyle\frac{400\times 4}{2000\times 100}$

  3. $\displaystyle\frac{400\times 100}{2000\times 4}$

  4. None of these


Correct Option: C
Explanation:

Principal = Rs 2000
Time = 4 years
Interest = Rs 400
Now, $Interest = \frac{Principal \times Rate \times Time}{100}$
$400 = \frac{2000\times R\times 4}{100}$
$R = \frac{400 \times 100}{2000 \times 4}$

At what rate percent per annum will the simple interest on a sum of money be 2/5 of the amount in 10 years?

  1. $4\frac {1}{2}$%

  2. $5\frac {1}{2}$%

  3. 4%

  4. 5%


Correct Option: C
Explanation:

$SI=\frac {2}{5}P, t=10, r=?$
$\frac {Ptr}{100}=\frac {2}{5}P$
or $\frac {10\times r}{100}=\frac {2}{5}$
or $r=\frac {20}{5}=4$%

A person finds that an increase in the rate of interest from $\displaystyle4\frac{7}{8}$% to $\displaystyle5\frac{1}{8}$% per annum increases his yearly income by Rs 30. His capital in rupees is

  1. 15,000

  2. 14,000

  3. 13,000

  4. 12,000


Correct Option: D
Explanation:

increase in rate of interest

$4\frac { 7 }{ 8 } =\frac { 39 }{ 8 } $
$5\frac { 1 }{ 8 } =\frac { 41 }{ 8 } $
$\frac { 41 }{ 8 } -\frac { 39 }{ 8 } =\frac { 2 }{ 8 } $
$\frac { 2 }{ 8 } $% of income is Rs30 of the capital
$1$% of income is $\frac { 8 }{ 2 } \times 30$ of capital
$100$% of income will be$\frac { 8 }{ 2 } \times 30\times 100=12000$
His capital in rupees is 12000

Anil invests Rs 3,000 for a year and Sunil joins him with Rs 2,000 after 4 months. After the year they receive a return of Rs 2,600. Sunil's share is

  1. Rs 800

  2. Rs 1,000

  3. Rs 750

  4. Rs 900


Correct Option: A
Explanation:

$Ratio\quad in\quad which\quad they\quad should\quad share\quad their\quad profits=Raio\quad of\quad investments\times \quad Time\quad period$

$=\frac { 3000\times 12 }{ 2000\times 8 } =\frac { 3\times 3 }{ 2\times 2 } =\frac { 9 }{ 4 } $
Sunils share will be$=\frac { 4 }{ 13 } \times 2600=800$
Sunils share will be Rs800,