The rate of the reaction, $C{ Cl } _{ 3 }CHO+NO\longrightarrow CH{ Cl } _{ 3 }+NO+CO$, is given by the equation, rate $=k\left[ C{ Cl } _{ 3 }CHO \right] \left[ NO \right] $. If concentration is expressed in ${mol}/{litre}$, the unit of $k$ is:
Tag: dependence of reaction rate on concentration of reactants
Questions Related to dependence of reaction rate on concentration of reactants
Units of rate constants for first and zero order reactions in terms of molarity $M$ unit are respectively:
Consider the reaction, $2A+B\longrightarrow $ Products. When the concentration of $B$ alone was doubled, the half-life did not change. When the concentration of $A$ alone was doubled, the rate increased by two times. The unit of the rate constant for this reaction is:
Consider following two reactions:
$A\longrightarrow $ Product, $-\dfrac { d\left[ A \right] }{ dt } ={ k } _{ 1 }{ \left[ A \right] }^{ 0 }$
$B\longrightarrow $ Product, $-\dfrac { d\left[ B \right] }{ dt } ={ k } _{ 2 }{ \left[ B \right] }^{ 1 }$
${ k } _{ 1 }$ and ${ k } _{ 2 }$ are expressed in terms of molarity $\left( mol\ { L }^{ -1 } \right) $ and time $\left( { s }\right) $ as:
Rate law expression of a reaction is:
Rate $=k{ \left[ A \right] }^{ { 2 }/{ 3 } }\left[ B \right] $
Which of the following are correct about the corresponding reaction?
Mechanism of a hypothetical reaction $X _2+Y _2\rightarrow 2XY$ is given below;
(i) $ X _2\rightarrow X+X$ (fast)
(ii) $X+Y _2\rightleftharpoons XY+Y$ (slow)
(iii) $ X+Y \rightarrow XY$ (fast)
The overall order of the reaction will be:
A reaction, which is second-order, has a rate constant of $0.002 L\, mol^{-1}\, s^{-1}$. If the initial conc. of the reactant is 0.2 M, how long will it take for the concentration to become 0.0400 M?
For the reaction $CO(g)+2{ H } { 2 }(g)\rightleftharpoons { CH } _{ 3 }OH(g)$. If active mass of $CO$ is kept constant and active mass of ${H} _{2}$ is tripled, the rate of forward reaction will become _____ of its initial value.
The reaction $2{NO} _{(g)}+{H} _{2(g)}\longrightarrow {N} _{2}{O} _{(g)}+{H} _{2}{O} _{(g)}$ follows the rate law $\cfrac { d{ P } _{ \left( { N } _{ 2 }O \right) } }{ dt } =k{ \left( { P } _{ NO } \right) }^{ 2 }{ p } _{ { H } _{ 2 } }$. If the reaction is initiated with ${P} _{NO}=1000mm$ $Hg$ and ${ p } _{ { H } _{ 2 } }=10mm$ $Hg$, then the reaction will follow:
The following data were obtained for the saponification of ethyl acetate using equal concentrations of ester and alkali. The reaction order is:
| Time(min) | 0 | 4 | 10 | 20 |
|---|---|---|---|---|
| Vol. of acid(mL) | 8.04 | 5.30 | 3.50 | 2.22 |