Tag: group 17 elements - trends in chemical properties

Questions Related to group 17 elements - trends in chemical properties

Correct order of hydrolysis of hexafluorides is?

  1. $TeF _6 > SeF _6 > SF _6$

  2. $ SF _6 > SeF _6 > TeF _6$

  3. $SF _6 > TeF _ > SeF _6$

  4. None of these


Correct Option: B

Which of the following trihalides on hydrosois produces hypochlorous acid?

  1. $PCl _{3}$

  2. $NCl _{3}$

  3. $BiCl _{3}$

  4. $SbCl _{3}$


Correct Option: B
Explanation:

Hydrolysis of $NCl$ gives $HOCl$ (hypochlorous acid)

${ NCl } _{ 3 }+{ 4H } _{ 2 }O\longrightarrow { N } _{ 4 }OH+3HOCl$

Which of the following can be hydrolysed?

  1. $TeF _6$

  2. $NCl _3$

  3. $SF _6$

  4. Both $1$ & $2$


Correct Option: A
Explanation:

$TeF _6$ canbe easily hydrolysed because of large size of Te central atom and low electronegativity the bond polarity of this bond is more .so, it is more reactive than other compounds like $SF _6$

$TeF _6+6H _2O\longrightarrow H _6TeO _6+6HF$

Which of the following is least stable?

  1. $Tl{I} _{3}$

  2. $Tl{F} _{3}$

  3. $Pb{F} _{4}$

  4. $Pb{I} _{4}$


Correct Option: D

Which is the correct order of decreasing basicity of halide ions?

  1. ${I}^{-1}> {Br}^{-}> {Cl}^{-}> {F}^{-}$

  2. ${F}^{-}> {Cl} _{-}> {Br}^{-}> {I}^{-}$

  3. ${Cl}^{-}> {Br}^{-}> {I}^{-}> {F}^{-}$

  4. ${F}^{-}> {Cl} _{-}> {I}^{-}> {Br}^{-}$


Correct Option: A,B

Which gas use in cooling tube in MRI tube ?

  1. He

  2. Ar

  3. $CO _2$

  4. $N _2$


Correct Option: A
Explanation:

He gas use as colling agent in super conducting magne

$PbI _4$ does not exist because :

  1. iodine is not a reactive

  2. $Pb(IV)$ is oxidizing and $I^-$ is strong reducing agent

  3. $Pb(IV)$ is less stable than $Pb(II)$

  4. $Pb^{4+}$ is not easily formed


Correct Option: C

Halogens have:

  1. high ionisation energies

  2. high electronegativities

  3. high electron affinities

  4. All the above


Correct Option: D
Explanation:

Halogens have high ionisation energies, high electronegativities and high electron affilities due to their smallest size in a particular period. As size decreases ionisation energy, elctronegativity and electron affinity increaes

Iodine is more soluble in aqueous solution of KlĀ because it forms soluble :

  1. $\mathrm{K}\mathrm{I} _{2}$

  2. $\mathrm{K}\mathrm{I} _{3}$

  3. $\mathrm{K}\mathrm{I} _{4}$

  4. $\mathrm{K} _{2}I _{2}$


Correct Option: B
Explanation:

$KI+I _2\rightarrow KI _3$ solubleĀ 
$\therefore $ Iodine is more soluble in KI (aq)

Iodine dissolves in aqueous Kl due to the formation of:

  1. $I^{-}$

  2. $ I _{2}^{-}$

  3. $ I _{3}^{-}$

  4. $I _{4}^{-}$


Correct Option: C
Explanation:

$KI\ (aq)\rightarrow K^{(+)}+I^-$

$I _2+I^-\rightarrow I _3 ^-$
$\therefore$ Iodine dissolves in KI (aq) due to the formation of $I _{3}^{-}$ ion.