Tag: uniform magnetic field lines of earth

Questions Related to uniform magnetic field lines of earth

In null method of comparison of magnetic moments, the net magnetic field at the centre of the DMM, when null deflection is obtained is

  1. $0$

  2. $B _{H}$

  3. between $0$ and $B _{H}$

  4. above $B _{H}$


Correct Option: B
Explanation:

In null method , two magnets are kept on either side of the arms so that the net deflection is zero . So the magnetic field due to the bar magnets gets cancelled and only earth's horizontal magnetic field is left

In both $\tan A$ and $\tan B$ positions in a Deflection Magnetometer,  the bar magnet is always placed

  1. parallel to the magnetic needle of the deflection magnetometer

  2. parallel to the aluminum pointer of the deflection magnetometer

  3. perpendicular to the aluminum pointer

  4. parallel to the arm having the wooden scale


Correct Option: A
Explanation:

In $\tan A$ position the bar magnet is placed horizontally, parallel to the arm of the deflection magnetometer and parallel to the magnetic needle of the deflection magnetometer. 

In $\tan B$ position the bar magnet is placed horizontally, perpendicular to the arm of the deflection magnetometer and parallel to the magnetic needle of the deflection magnetometer

The absolute value of earths magnetic horizontal intensity is determined with the help of

  1. DMM only

  2. VMM only

  3. DMM & VMM

  4. Plane mirror


Correct Option: C
Explanation:

The absolute value of earths magnetic horizontal intensity is determined with the help of DMM and VMM.

Among the following statements: 

A) In $\tan A$ position of deflection magnetometer $B$ and $B _{H}$ are perpendicular 

B) In $\tan B$ position of deflection magnetometer $B$ and $B _{H}$ parallel

  1. A true & B false

  2. A false & B true

  3. A and B are true

  4. A and B are false


Correct Option: A
Explanation:

In $\tan A$ position , the arms are in east-west direction and the compass needle is in north-south direction and the bar magnet is kept parallel to the arms, perpendicular to the compass needle.

In $\tan B$ position , the arms are in north-south direction and the compass needle is in same direction , the magnet is kept in east - west direction , perpendicular to the compass needle.

The restoring couple for a magnet oscillating in the vibration magnetometer is provided by

  1. horizontal component of earths magnetic field

  2. gravity

  3. torsion in the suspended thread

  4. magnetic field of magnet


Correct Option: A
Explanation:

When the bar magnet in vibration magnetometer is displaced from the earth's magnetic field , the torque acts on it to allign it with the earth's magnetic field . So the earth's magnetic field is  the restoring force.

Assertion (A) : In deflection magnetometer a short magnetic needle is arranged in the compass box
Reason (R) : The magnetic needle is found in the uniform magnetic field produced by earth and bar magnet
  1. Both A and R are true and R is the correct explanation of A

  2. Both A and R are true and R is not correct explanation of A

  3. A is true, But R is false

  4. A is false, But R is true


Correct Option: A
Explanation:

In Deflection magnetometer ,the bar magnet is kept at a distance from the magnetic needle and the deflection thus observed is due to the earth's and bar magnet's magnetic field..

Deflection magnetometer is held in $\tan B$ position. A magnet placed on one of its arms produces no deflection. This implies that the axis of the magnet is

  1. in the east - west direction

  2. in the north-south direction

  3. perpendicular to the wooden bench

  4. North - East


Correct Option: B
Explanation:

In $\tan B$ position , the arms are in the north south direction and the aluminium pointer are in east- west direction. So the compass needle is in north- south direction. For the magnetic field lines of the magnet to be ineffective then they must be in the north south direction so that they will not create a torque.

If the magnet is in east- west direction , a couple acts on the magnet and thus causes deflection.

The magnets of same magnetic moment $M$ and different lengths are placed in $tan\; A$ position. The fields at equal distances from them are :

  1. greater for long magnet

  2. greater for small magnet

  3. equal for both

  4. zero


Correct Option: A
Explanation:

In tan A position , the magnetic field due to the bar magnet is given by
$\dfrac{\mu _o}{4 \pi} \dfrac{2Md}{(d^2 - l^2)^{3/2}} = B$ for a bar magnet
where $ l $ is the length of the magnet and $ d $ is the distance of the point from the centre of the magnet.
For the same distance $ d $ and the same magnetic moment, strength of the magnetic field
$ B \propto \dfrac{1}{(d^2-l^2)^\dfrac{3}{2}} $
So larger the length of the magnet, greater is the value of $ \dfrac{1}{(d^2-l^2)^\dfrac{3}{2}} $ and consequentially, the strength of the magnetic field.
So , magnetic field at a point is larger for long bar magnet

A D.M.M is in tan A position in a region where $B _H$  is 50$\mu $T. When a magnet is placed at a suitable distance the deflection obtained is 45$^{0}$. The resultant magnetic field at the centre of the compass is

  1. 50$\mu $T

  2. $50\sqrt{2}\mu \top $

  3. 25 $\mu $ T

  4. 100$\mu $ T


Correct Option: B
Explanation:

The magnetic field due to the magnet is B $ = B _H  tan \theta $
$ B = B _H tan 45 = B _H$
Total magnetis field at the centre is 
$ B _T= \sqrt{B^2 + B _H ^2}= \sqrt{2}{B _H} $
$B _T = 50 \sqrt{2}\mu $T

To measure the magnetic moment of a bar magnet, one may use.

  1. a tangent galvanometer.

  2. a deflection galvanometer if the earth's horizontal field is known.

  3. an oscillation magnetometer if the earth's horizontal field is known.

  4. both deflection and oscillation magnetometer if the earth's horizontal field is not known.


Correct Option: B,C,D
Explanation:

To measure the magnetic moment of a bar magnet,
a deflection galvanometer is used  if the earth's horizontal field is known.
An oscillation magnetometer  can be used if the earth's horizontal field is known.
Both deflection and oscillation magnetometer can be used  if the earth's horizontal field is not known since there are two variables.