Tag: nitrogen and sulfur

Questions Related to nitrogen and sulfur

Which of the following element occurs in free form in nature?

  1. $N$

  2. $P$

  3. $As$

  4. $Sb$


Correct Option: A
Explanation:

Nitrogen occurs in the free state as $N _2$ as it has less size it has more tendency to from pi bonds with same elements and get stability.
Hence option  A is correct.

$2N 2+O _2 \longrightarrow $ _________ ?

  1. $N _2O$

  2. $NO _2$

  3. $NO$

  4. $N _2O _2$


Correct Option: A
Explanation:

Nitrogen and oxygen react to form nitrous oxide.


$2N _2 + O _2 \rightarrow 2N _2O$

${ N } _{ 2 }(g)\ +\ { 3H } _{ 2 }(g)\rightleftharpoons { 2NH } _{ 3 }(g)$


For the reaction initially the mole was 1 : 3 of $N _2$ and ${ H } _{ 2 }$. At equilibrium 50% of each has reacted. If the equilibrium pressure is p, the partial pressure of ${ NH } _{ 3 }$ at equilibrium is :

  1. $\dfrac { p }{ 3 }$

  2. $\dfrac { p }{ 4 }$

  3. $\dfrac { p }{ 6 }$

  4. $\dfrac { p }{ 8 }$


Correct Option: A
Explanation:
$N _2 + 3H _2⇌2NH _3$
  1           3             0
(1-$x$)  ($3-3x$)     $2x$
            
$1-x =  \dfrac{1}{2}$
$\therefore x=\dfrac{1}{2}$
Mole of $H _2 = $ 1.5 mol
Mole of $N _2 = $ 0.5 mol
Mole of $NH _3 = $ 1.0 mol
Now,
Mole fraction of $NH _3$ =$\dfrac{1}{3}$

partial pressure = $p*\dfrac{1}{3}=\dfrac{p}{3}$

Gas B is paramagnetic and support the combustion compound B is :

  1. $N _2$

  2. $N _2O$

  3. $O _2$

  4. $Na _2O$


Correct Option: C
Explanation:

$O _2$ is paramagnetic due to the presence of $2$ unpaired $e^-$ in the $\Pi$-antibonding orbital.

$\sigma1s^2\sigma^*1s^2\sigma2s^2\sigma^*2s^2\sigma2p _3^2\Pi2p _x^2=\Pi2p _y^2\Pi^*2p _x^1=\Pi^*2p _y^1$
Also, $O _2$ supports combustion as it does not burn but it is an oxidizer, it oxidizes other reactive materials, itself getting reduced.

Which compound does nitrogen have oxidation number in fraction?

  1. $NH _{2}OH$

  2. $N _{2}H _{4}$

  3. $NH _{3}$

  4. $N _{3}H$


Correct Option: D

How many of the following compound on thermal decomposition gives $N _2$ gas?
$(NH _4) _2 Cr _2 O _7$, $NH _4 NO _3$, $NH _4 IO _3$, $NH _4 NO _2$, $Ba(N _3) _2$, $Ba(NO _3) _2$, $(NH _4) _2 SO _4$, $(NH _4) _2 CO _3$

  1. 2

  2. 3

  3. 4

  4. 5


Correct Option: B
Explanation:

$(NH _4) _2Cr _2O _7\longrightarrow N _2+Cr _2O _3+H _2O$

$NH _4NO _3\longrightarrow N _2O+2H _2O$
$NH _4IO _3\longrightarrow$
$NH _4NO _2\longrightarrow N _2+2H _2O$
$Ba(N _3) _2\longrightarrow Ba+3N _2$
$Ba(NO _3) _2\longrightarrow BaO+NO _2+O _2$
$(NH _4) _2SO _4\longrightarrow NH _4HSO _4+NH _3$
$(NH _4) _2CO _3\longrightarrow 2NH _3+CO _2+H _2O$
$\therefore$ Answer is option B=3

All metals react with nitrogen on heating.
  1. True

  2. False


Correct Option: B

The mixed anhydride of nitrogen is:

  1. ${N} _{2}{O} _{2}(2NO)$

  2. ${N} _{2}{O} _{4}(2{NO} _{2})$

  3. ${N} _{2}{O} _{5}$

  4. ${N} _{2}{O} _{2}$


Correct Option: A
Explanation:
Mixed anhydride or double acid anhydride is the compound that reacts with water to form a mixture of two acidic anhydride.
Two oxides of nitrogen are acid anhydrides; that is, they react with water to form two nitrogen-containing oxyacids.

$2NO _2 + H _2O \longrightarrow HNO _3 + HNO _2$
 
Hence, the correct option is B.

The mixed anhydride of nitrogen is:

  1. $N _2O _2(2NO)$

  2. $N _2O _4(2NO _2)$

  3. $N _2O _5$

  4. $N _2O _3$


Correct Option: B
Explanation:

$NO _2$ is called as a mixed anhydride of nitrogen because it gives a mixture of $ HNO _2$ and $HNO _3$. Hence option (B) is correct .

An orange solid (X) on heating, gives a colourless gas (Y) and a only green residue (Z). Gas (Y) on treatment with Mg, produceds a white solid substance................

  1. $Mg _{3}N _{2}$

  2. $MgO$

  3. $Mg _{2}O _{3}$

  4. $MgCl _{2}$


Correct Option: A
Explanation:

$(NH _4) _2Cr _2O _7  \rightarrow N _2 + Cr _2O _3 + 4H _2O$
$3Mg + N _2 \rightarrow Mg _3N _2$
Orange solid is $(NH _4) _2Cr _2O _7$
Colourless gas is $N _2$
Green residue is $Cr _2O _3$