Tag: nitrogen and sulfur

Quizzes (10) Questions (295)

Questions Related to nitrogen and sulfur

Multiple choice chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

Ammonia reacts with excess of chlorine to form :

  1. ${ N } _{ 2 }+N{ H } _{ 4 }Cl$
  2. $N{ Cl } _{ 3 }$ and $HCl$
  3. $N{ H } _{ 4 }Cl$ and $N{ Cl } _{ 3 }$
  4. ${ N } _{ 2 }$ and $HCl$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Pure chlorine gas may react vigorously with ammonia gas. An excessive mix of the two gases in air can produce hazardous compounds such as nitrogen trichloride.

The following reaction takes place:

$N{ H } _{ 3 }+3{ Cl } _{ 2 }\longrightarrow N{ Cl } _{ 3 }+3HCl$

Ammonia reacts with excess of chlorine to form $ N{ Cl } _{ 3 } $ and $ HCl $.

Multiple choice chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

Which of the following compounds are formed by the reaction of ammonia with acids?

  1. Calcium ammonium nitrate

  2. Ammonium chloride

  3. Ammonium phosphate

  4. Ammonium sulphate
Reveal answer Fill a bubble to check yourself
A,B,C,D Correct answer
Explanation

$ { NH } _{ 3 }+{ HNO } _{ 3 }\longrightarrow { NH } _{ 4 }NO\ { NH } _{ 3 }+HCl\longrightarrow { NH } _{ 4 }Cl\ { NH } _{ 3 }+{ H } _{ 4 }{ PO } _{ 4 }\longrightarrow ({ { NH } _{ 4 }) } _{ 3 }{ PO } _{ 4 }\ { NH } _{ 3 }+{ H } _{ 2 }{ SO } _{ 4 }\longrightarrow { { (NH } _{ 4 }) } _{ 2 }{ PO } _{ 4 }\  $

All of the above in respective order. 

Multiple choice chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

Ammonia gas cannot be dried by passing through :

  1. $conc.{ H } _{ 2 }S{ O } _{ 4 }$
  2. anhydrous $CaO$
  3. ${ P } _{ 2 }{ O } _{ 5 }$
  4. $CuS{ O } _{ 4 }$
Reveal answer Fill a bubble to check yourself
A,C Correct answer
Explanation

Because ammonia and water will form some amount of ammonium hydroxide, $N{ H } _{ 4 }OH$. The hydroxide will react with the acid ${ H }^{ + }$ ions from the acid and forms water. Addition of an acid to even a mild base like $N{ H } _{ 4 }OH$ is counter-productive to drying.

Multiple choice chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

Identify the probable products for the reaction of $N{ H } _{ 3 }$ with ${ Cl } _{ 2 }$.

  1. ${ N } _{ 2 }$ and $N{ H } _{ 4 }Cl$
  2. $N{ Cl } _{ 3 }$ and $HCl$
  3. ${ N } _{ 2 }$ and $N{ Cl } _{ 3 }$
  4. $N{ H } _{ 4 }Cl$ and $HCl$
Reveal answer Fill a bubble to check yourself
A,B Correct answer
Explanation

Possible reactions of $N{ H } _{ 3 }$ and ${ Cl } _{ 2 }$ are :

  1. $N{ H } _{ 3 }+{ Cl } _{ 2 }\longrightarrow { N } _{ 2 }+N{ H } _{ 4 }Cl$
  2. $N{ H } _{ 3 }+{ Cl } _{ 2 }\longrightarrow N{ C }l _{ 3 }+HCl$

Multiple choice chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

Which of the following has highest proton affinity:

  1. Stilbine

  2. Arsine

  3. Phosphine

  4. Ammonia
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

As the size of the nitrogen in ammonia is less than the other elements in the hydrides of that group ammonia has the more affinity towards the proton than the any other hydride of that group like phosphine, stobine and arsine.
Hence option D is correct.

Multiple choice chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

$NH _3$ gas is liquefied more easily than $N _2$. Hence:

  1. vander Waals' constants a and b of $NH _3$ > that of $N _2$
  2. vander Waals' constants a and b of $NH _3$ < that of $N _2$
  3. $a(NH _3)$ > $a(N _2)$ but $b(NH _3)$ < $b(N _2)$
  4. $a(NH _3)$ < $a(N _2)$ but $b(NH _3)$ > $b(N _2)$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation
  • In vander Wall's equation of state, the constant 'a' provides a correction for the intermolecular forces. Constant 'b' is a correction for finite molecular size and its value is the volume of one mole of the atoms or molecules.
  • For a gas which is easily liquifiable value of 'a' will be more and value of 'b'  will be less.
  • Hence in the question it is given that $NH _3$ is liquefied more easilt than $N _2$ and hence $a(NH _3)>a(N _2)$ but $b(NH _3)<b(N _2)$.

Multiple choice chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

What is the amount of hear released when $3.4$ gm $NH _3$(g) and $6.4$gm $O _2$(g) react at constant temperature and pressure by the following equation.
$4NH _3$(g) + $5O _2$ (g) \rightarrow $4NO(g)$ + $6H _2O$(g) . $\Delta _1H^0 = 900 k.$

  1. $45$ kJ
  2. $250$ kJ
  3. $36$ kJ

  4. None of these
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The molecular weights of $\displaystyle NH _3$ and $\displaystyle O _2$ are 17 g/mol and 32 g/mol respectively.
3.4 g $\displaystyle NH _3 = \dfrac {3.4 \ g}{ 17 \ g/mol}=0.2 \ mol$
6.4 g $\displaystyle O _2= \dfrac {6.4 \ g}{32 \ g/mol}=0.2 \ mol$
0.2 moles of $\displaystyle O _2$ will react with $\displaystyle 0.2 \times \dfrac {4}{5}=0.16$ moles of $\displaystyle NH _3$. But 0.2 moles of
$\displaystyle NH _3$ are present. Hence, $\displaystyle O _2$ is the limiting reagent and $\displaystyle NH _3$ is excess reagent.

When 5 moles of $\displaystyle O _2$ react, the heat released is 900 kJ.
When 0.2 moles of $\displaystyle O _2$ react, the heat released will be
$\displaystyle 900 \ kJ \times \dfrac { 0.2}{5}=36 \ kJ$.

Multiple choice chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

Hypotism is a powerful art of suggestion. Under the influence of hypnotism, subjects may report as normal, a slightly smell from:

  1. A source of pure hydrogen gas

  2. An ammonia bottle

  3. An oxygen cylinder

  4. A source of pure nitrogen gas
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Ammonia has a strong smell which can be easily detected even from meters of distances. Hence, a slight smell of ammonia bottle can be detected.