$ \sqrt { 3 } \ cosec 20 ^ { \circ } - \sec 20 ^ { \circ }$ is equal to :
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Tag: using trigonometric tables
Questions Related to using trigonometric tables
$Tan \,25^o.Tan \,31^o + Tan \,31^o.Tan \,34^o + Tan \,34^o .Tan \,25^o =$
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Let $x=\sin 1^{o}$, then the value of expression
$\dfrac {1}{\cos 0^{o}\cos 1^{o}}+\dfrac {1}{\cos 1^{o}\cos 2^{o}}+\dfrac {1}{\cos 2^{o}\cos 3^{o}}+....+\dfrac {1}{\cos 44^{o}\cos 45^{o}}=$
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$\dfrac{\cos (45^0+A)-\cos(45^0-A)}{\sin(120^0+A)-\sin(120^0-A)}=?$
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if $A=30$ then the value of $\cos 2A$ is
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$(1+\tan 5^{o})(1+\tan 10^{o})(1+\tan 15^{o}).....(1+\tan 45^{o})$ is equal to
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$sin 12^o\sin\ 24^o\sin\ 48^o\sin\ 84^o$=
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$\tan 5\tan 25\tan 30\tan 65 \tan 85$ is equal to
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$\tan 20 ^ { \circ } + \tan 40 ^ { \circ } + \sqrt { 3 } \tan 20 ^ { \circ } \tan 40 ^ { \circ }$ is equal to
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If $\alpha =685^o$, then $(\cos\alpha -\sin\alpha)$ is equivalent to?
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