Tag: using trigonometric tables

Values of : $sin{ 10 }^{ 0 }sin{ 50 }^{ 0 }sin{ 60 }^{ 0 }sin{ 70 }^{ 0 }$ is

$sin^21^0+sin^22^0+sin^23^0+....+sin^290^0$

$\frac { cos{ 70 }^{ \circ  } }{ sin{ 20 }^{ \circ  } } +\frac { cos{ 59 }^{ \circ  } }{ sin{ 31 }^{ \circ  } } -8{ sin }^{ 2 }{ 30 }^{ \circ  }$

The value of $(4 \, cos^2 9^o - 1) (4 cos^2 27^o - 1) (4 \, cos^2 81^o - 1) (4 \, cos^2 243^o - 1) $ is 

$sin{ 40 }^{ \circ  }{ 35 }^{ | }cos{ 19 }^{ \circ  }{ 25 }^{ | }+cos{ 40 }^{ \circ  }{ 35 }^{ | }sin{ 19 }^{ \circ  }{ 25 }^{ |= }$

$\sqrt {3}\csc 20^{o}-\sec 20^{o}$ is equal to

$tan{ 40 }^{ \circ  }+tan{ 80 }^{ \circ  }-\sqrt { 3 } tan{ 40 }^{ \circ  }tan{ 80 }^{ \circ  }=$

$\sin^{-1}\left(\sin 100\right)+\cos^{-1}\left(\cos 100\right)+\tan^{-1}\left(\tan 100\right)+\cot^{-1}\left(\cot 100\right)$ equals to 

$\dfrac{tan225 cot81cot69}{cot261 + tan21} $ = 

Find the value of, $\dfrac {4}{3}\cot^{2}30^{o}+\cot^{2}60^{o}-2\csc ^{2}60^{o}-\dfrac {3}{4}\tan^{2}30^{o}$