Tag: theory of equations

Questions Related to theory of equations

Multiple choice reciprocal equations theory of equations maths

The equation $3x^4-5x^3+3x^2-4x+5=0$ is of the type

  1. Quadratic

  2. Linear

  3. Reiprocal

  4. None of the above

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Given equation is $3x^4-5x^3+3x^2-4x+5=0$ .... $(i)$

The maximum power of $x$ in this equation is $ 4$, so this is $4th$ degree equation  
So, $(i)$ is neither linear nor quadratic equation.
In reciprocal equation ($ ax^4 +bx^3 +cx^2 +dx +e = 0 $)  the multiplication of the roots i.e ($\dfrac{e}{a}$) should be  $1$

In the given equation $(i)$, $\dfrac{e}{a}  = \dfrac{5}{3}$  
So the multiplication of roots is not equal to one
Therefore, equation $(i)$ is not a reciprocal equation.

Hence, option D is correct.

Multiple choice reciprocal equations theory of equations maths

$x+\dfrac{1}{x}=2, x^{1680}+\dfrac{1}{x^{1680}}$

  1. $1$
  2. $-1$
  3. $2$
  4. $-2$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

We have,

$x+\dfrac{1}{x}=2$
We know that if $x+\dfrac{1}{x}=2$, then
$x^n+\dfrac{1}{x^n}=2$
Therefore,
$x^{1680}+\dfrac{1}{x^{1680}}=2$

Multiple choice reciprocal equations theory of equations maths

Simplify the reciprocal equation $\dfrac{3}{12}=\dfrac{3}{2x}$

  1. $0$
  2. $3$
  3. $6$
  4. $1$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Given equation is $\dfrac {3}{12}=\dfrac {3}{2x}$

$\Rightarrow 6x=36$
$\Rightarrow x=\dfrac {36}{6}$
$\Rightarrow x=6$
Therefore, the reciprocal of the given function is $6$.

Multiple choice reciprocal equations theory of equations maths

Simplify $\sqrt { 1+{ \left( \cfrac { { x }^{ 4 } }{ -2{ x }^{ 2 } }  \right)  }^{ 2 } } $

  1. $\cfrac { { x }^{ 4 }+1 }{ 2{ x }^{ 2 } } $
  2. $\cfrac{\sqrt{{x}^{2}+1}}{2}$
  3. $\cfrac{{x}^{4}+2{x}^{2}-1}{2{x}^{2}}$
  4. $\cfrac { { x }^{ 4 }-1 }{ 2{ x }^{ 4 } } $
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$\sqrt{1+(\dfrac{x^4}{-2x^2})^2}$


$\Rightarrow \sqrt{1+\dfrac{x^8}{4x^4}}$

$\Rightarrow \sqrt{\dfrac{4x^4+x^8}{4x^4}}$

$\Rightarrow \dfrac{\sqrt{4x^4+x^8}}{2x^2}$

$\Rightarrow\cfrac{\sqrt{{x}^{2}+1}}{2}$

Multiple choice reciprocal equations theory of equations maths

The equation $2x^4-9x^3+14x^2-9x+2=0$ is of the type

  1. Quadratic equation

  2. Linear equation

  3. Reciprocal Equation

  4. None

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Given equation is $2x^4-9x^3+14x^2-9x+2=0$ .... $(i)$

The maximum power of $x$ in this equation is $ 4$, so this is $4th$ degree equation  
So, it is neither linear nor quadratic equation.
In reciprocal equation $ ax^4 +bx^3 +cx^2 +dx +e = 0 $, the multiplication of the roots i.e ($\dfrac{e}{a}$) should be  $1$

In the given equation $(i)$, $\dfrac{e}{a}  = \dfrac{2}{2}$  
So the multiplication of roots is equal to one
Therefore, equation $(i)$ is a reciprocal equation.

Hence, option C is correct.

Multiple choice reciprocal equations theory of equations maths

What is a reciprocal equation?

  1. It involves reciprocal of the given variable.

  2. It involves square of the given variable.

  3. It involves squareroot of the given variable.

  4. It involves square and reciprocal of the given variable.

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Reciprocal is said to be divide $1$ by a number. Reciprocal equation involves reciprocal of the given number.

Multiple choice reciprocal equations theory of equations maths

Determine the root of the equation: $\dfrac{9}{x}-\dfrac{7}{x}=1$

  1. $x=2$
  2. $x=-2$
  3. $x=1$
  4. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Given reciprocal equation can be written as

$\dfrac{9}{x}=\dfrac{7+x}{x}$
Cancelling out the denominator on both side, we get
$9=7+x$
$\Rightarrow x=2$
Hence, option A is correct.

Multiple choice reciprocal equations theory of equations maths

Which of the following is not a reciprocal function?

  1. $f(x)=\dfrac{1}{x}$
  2. $f(x)={x}^{-1}$
  3. $f(x)=x$
  4. None of the above

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

This is the reciprocal function:

$f(x)=\dfrac {1}{x}$
Its domain is the real numbers, except $0$, because $\dfrac {1}{0}$ is undefined.
The reciprocal function can also be written as an exponent.
$f(x)=x^{-1}$

Multiple choice reciprocal equations theory of equations maths

$\cfrac { \left( 2x-1 \right) { \left( x-1 \right)  }^{ 4 }{ \left( x-2 \right)  }^{ 4 } }{ (x-2){ \left( x-4 \right)  }^{ 4 } } \le 0$

  1. $(\dfrac{1}{2},2)$
  2. $R$
  3. $\phi$
  4. $(1/3,2)$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

$\dfrac{(2{x}-1)(x-1)^{4}(x-2)^{4}}{(x-2)(x-4)^{4}} \le 0\implies x\neq 2$


$(2{x}-1)(x-1)^{4}(x-2)^{3}\le 0$


$(x-\dfrac{1}{2})(x-2)^{3}\le 0$

$x\in \bigg(\dfrac{1}{2},2\bigg)$

Multiple choice reciprocal equations theory of equations maths

If $b$ is a root of a reciprocal equation, $f(x)=0$, then another root of $f(x)=0$ is:

  1. $\dfrac{-1}{b}$
  2. $\dfrac{1}{b^2}$
  3. $\sqrt b$
  4. $\dfrac{1}{b}$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

A reciprocal equation is an equation whose roots can be divided into pairs of numbers, each the reciprocal of the other. 

(equivalently) an equation which is unchanged if the variable $x$ is replaced by its reciprocal $\dfrac{1}{x}$ is reciprocal equation.
Since one root is $b$, then the other root is $\dfrac{1}{b}$

Hence, option D is correct.