Tag: measurement of area, volume and density

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Questions Related to measurement of area, volume and density

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Which of the following is used to measure the volume of a regular shaped object?

  1. Metre scale

  2. Vernier callipers

  3. Screw guage

  4. All of these
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

To find the volume of a regular shaped object ,first its dimensions are measured using either a metre scale, a vernier callipers or a screw gauge and then volume is calculated using corresponding relations.

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

What is best way to measure the volume of an irregularly shaped solid?

  1. By using a beam balance

  2. By using water displacement

  3. By using a ruler to measure the length of each side of the object

  4. By using formula : length x width x height
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Water displacement is the standard method for measuring the volume of an irregularly shaped solid. The object is submerged in a graduated cylinder, and the volume of water displaced equals the volume of the object.

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Choose the INCORRECT statement from the following.

  1. Volume is a chemical property of matter

  2. Volume is a physical property of matter

  3. Volume is needed to find density

  4. Volume is the amount of space something takes up
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Option D is the definition of Volume. It is only a physical property of any object and has nothing to do with the chemical properties. Since density is mass/ volume, it is necessary to find density.

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Which of the following is used to measure the volume of a liquid or an irregular shaped object?

  1. A burette

  2. A measuring flask

  3. A measuring cylinder

  4. All of these
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Volume of a liquid or an irregular solid object is measured with the help of burettes, measuring flasks and measuring cylinders.

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Which of the following is not used to measure the volume of a liquid or an irregular shaped object?

  1. A pipette

  2. A measuring flask

  3. A graduated cylinder

  4. A meter scale
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

A liquid or an irregular shaped object does not have a geometric shape. So, by measuring its certain dimensions, volume may not be calculated. Hence a meter scale can not be used to measure the volume of a liquid or an irregular shaped object.

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Find the volume of a ring immersed in water ,increasing the level from 55.2 ml to 75.3 ml.

  1. $20.1\ ml$
  2. $29\ ml$
  3. $10.1\ ml$
  4. $14.1\ ml$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Initial volume level   $V _i = 55.2 \ ml$
Final volume level   $V _f = 75.3 \ ml$
Thus, volume of ring    $V = V _f-V _i$
$\implies \ V = 75.3-55.2 = 20.1 \ ml$

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

The volume enclosed by the cylinder of diameter $1.06\ m$  and height 7.2 m to the correct no. of the significant figure is:

  1. $6.350\ m^3$
  2. $6.35\ m^3$
  3. $6.3\ m^3$
  4. $6\ m^3$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Diameter of cylindrical vessel  $d = 1.06 \ m$
Height of cylindrical vessel  $h = 7.2 \ m$
Volume   $V = \dfrac{\pi d^2 h}{4}$
$\implies \ V = \dfrac{\pi\times (1.06)^2\times 7.2}{4} = 6.354 \ m^3$
Since the number $7.2$ has two significant figures and $1.06$ has three significant figures.
So the final answer must have 2 significant figures.
Thus volume of cylinder   $V = 6.3 \ m^3$

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Volume enclosed by the sphere of diameter $1.06\ m$ to the correct no. of significant figure is:

  1. $0.62329 \ m^3$
  2. $0.623 \ m^3$
  3. $0.6232 \ m^3$

  4. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The significant figures are the number of digits in a value, that are significant. In $1.06m$, the number of significant figures is 3. In the answer also we must maintain 3 significant figures only. Hence option B is correct.

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

The density of steel rod is $7850\ kg/m^3$, its mass is $5\ kg$.Find its volume?

  1. $7.36\times 10^{-4}\ m^3$
  2. $36\times 10^{-4}\ m^3$
  3. $6.36\times 10^{-4}\ m^3$
  4. $6\times 10^{-4}\ m^3$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Mass of steel rod $m = 5 \ kg$
Density of steel rod   $d = 7850 \ kg/m^3$
Volume of steel rod  $V = \dfrac{m}{d}$
$\implies \ V = \dfrac{5}{7850} = 6.36\times 10^{-4} \ m^3$