Tag: money math

Questions Related to money math

The difference between a discount of $40\%$ of Rs. $1000$ and two successive discount of $30\%$ and $10\%$ on the same amount is:

maths money math different discounts successive discounts problems on discounts

  1. $0$

  2. $20$

  3. $30$

  4. $40$

Show answer
Correct Option: C
Explanation:

A discount of $40\%$ on Rs. $1000 = \dfrac{40}{100}\times 1000$ 

                                                     $=$ Rs. $400$ 

Two Successive discounts of $30\%$ and $10\%$ reduces price to $= 1000 \times \dfrac{100-30}{100} \times \dfrac{100-10}{100}$
                                                                                                      $=$ Rs. $630$
$\Rightarrow$ Discount $= 1000-630 = 370$

Difference in discount $= 400-370 = 30$

The marked price of an article is Rs. $500$. It is sold at successive discounts of $20\%$ and $10\%$. The selling price of the article (in Rs.) is

maths money math different discounts successive discounts problems on discounts

  1. $350$

  2. $375$

  3. $360$

  4. $400$

Show answer
Correct Option: C
Explanation:

M.P. $=$ Rs. $500$, $1^{st}$ discount $ = 20\%$
Net price after $1^{st}$ discount $= 80\%$ of Rs. $500=\dfrac {80}{100}\times 500=$ Rs. $400$
$2^{nd}$ discount $= 10\%$
$\therefore$ Final S.P. after $2^{nd}$ discount $=\dfrac {90}{100}\times 400$
$=$ Rs. $360$

A shopkeeper allows a discount of $10\%$ on his goods. For cash payments, he further allows a discount of $20\%$. Find a single discount equivalent of the above offer

maths money math different discounts successive discounts problems on discounts

  1. $25\%$

  2. $28\%$

  3. $32\%$

  4. $35\%$

Show answer
Correct Option: B
Explanation:

Let the M.P. $=$ Rs. $ 100$,
$\therefore$ S.P. $=80\%$ of $90\%$ of Rs. $ 100=$ Rs. $ \left (\dfrac {80}{100}\times \dfrac {90}{100}\times 100\right )=$ Rs. $  72$
$\therefore$ Single discount $=$ Rs. $ 100-$ Rs. $ 72=$ Rs. $ 28$
Single discount rate $=\dfrac {28}{100}\times 100=28\%$.

Find the selling price of an article, if a shopkeeper allows two successive discount of $5\%$ each on the marked price of Rs. $ 80$

maths money math different discounts successive discounts problems on discounts

  1. Rs $61.70$

  2. Rs $67.30$

  3. Rs $72.20$

  4. Rs $77.10$

Show answer
Correct Option: C
Explanation:

Given, M.P$=$ Rs. $80$

Two successive  Discount each $=5\%$

$\therefore $ S.P after first discount$=80-5\%$ of $80$

$\Rightarrow 80-\dfrac{5}{100}\times 80$

$\Rightarrow 80-4=$ Rs. $76$

Selling price after second discount $=76-5\% $ of $  76$

$\Rightarrow 76-\dfrac{5}{100}\times 76$

$\Rightarrow 76-3.80=$ Rs. $72.20$

The marked price of a watch is Rs 800. A customer gets two successive discounts on the marked price, the first being 10%. What is the second discount if the customer pays Rs 612 for it?

maths money math different discounts successive discounts problems on discounts

  1. 14%

  2. 15%

  3. 17%

  4. 18%

Show answer
Correct Option: B
Explanation:

$M.P. =Rs 800$, First discount $=$ 10%
$\therefore$ Net price after the first discount $= 90$% of $Rs 800 = 0.9 \times Rs 800 =Rs 720$
Final price after the second discount $=Rs 612$
$\therefore$ Second discount $=Rs 720 -Rs 612 =Rs 108$
$\Rightarrow$ Second discount rate $=\frac {108}{720}\times 100$% $= 15$%.

A single discount equivalent to successive discounts of $30\%, 20\%$ and $10\%$ is

maths money math different discounts successive discounts problems on discounts

  1. $50\%$

  2. $51\%$

  3. $49.4\%$

  4. $49.6\%$

Show answer
Correct Option: D
Explanation:

Let the M.P. $=$ Rs. $ 100$
Then, S.P. after $1^{st}$ discount of $30\%$
$=100-30\%$ of Rs. $ 100 =100-\dfrac{30}{100}\times 100=$ Rs. $ 70$
S.P. after $2^{nd}$ discount of $20\%$
$\Rightarrow 70-$ $20\%$ of Rs. $ 70 =70-\dfrac{20}{100}\times 70$
$\Rightarrow 70-14=$ Rs. $ 56$
Net S.P. after $3^{rd}$ discount of $10\%$
$=56- 10\%$ of Rs. $ 56=56-\dfrac{10}{100}\times 56$

$\Rightarrow 56-5.60 =$ Rs. $ 50.4$
$\therefore$ Total discount $=$ Rs. $ 100-$ Rs. $ 50.4=$ Rs. $ 49.6$
Discount rate $=\dfrac {49.6}{100}\times 100=49.6\%$

A dealer buys a car listed at Rs. $200000$ at successive discounts of $5$ $\%$ and $10$ $\%$. If he sells the car for Rs. $179550$, then his profit is

maths money math different discounts successive discounts problems on discounts

  1. $10$ $\%$

  2. $9$ $\%$

  3. $5$ $\%$

  4. $4$ $\%$

Show answer
Correct Option: C
Explanation:

CP, of the car $=$ $95\%$ of $90\%$ of Rs. $ 200000$

$\Rightarrow \dfrac{95}{100}\times \dfrac{90}{100}\times 200000$
$\Rightarrow 95\times 90\times 20=Rs 171000$
S.P. of the car $=$ Rs. $ 179550$
$\therefore$ Profit $\%$ $=\left (\dfrac {(179550-171000)}{171000}\times 100\right )$ $\%$
$=\left (\dfrac {8550}{171000}\times 100\right )$% $=$ $5$%

A dealer buys a table listed at Rs 1500 and gets successive discounts of 20% and 10%. He spends Rs 20 on transportation and sells it a profit of 10%. Find the selling price of the table

maths money math different discounts successive discounts problems on discounts

  1. Rs $1800$

  2. Rs $1650$

  3. Rs $1188$

  4. Rs $1210$

Show answer
Correct Option: D
Explanation:

$\Rightarrow$  M.P of table is Rs. 1500

$\Rightarrow$  Discount percent allowed for first time is 20%
$\Rightarrow$  Price after discount = M.P - Discount 
$\Rightarrow$  Price after discount = $1500-\dfrac{20}{100}\times 1500=Rs.1200$
$\Rightarrow$  Discount percent allowed for the second time is 10%
$\Rightarrow$  Price after discount = $1200 - \dfrac{10}{100}\times 1200=Rs.1080$
$\Rightarrow$  Other cost = $Rs.20$
$\Rightarrow$  Total C.P = Rs. 1080 + Rs. 20 = Rs. 1100
$\Rightarrow$  Profit percent earned by selling the table is 10%.
$\therefore$    S.P of table = C.P + Profit
$\Rightarrow$  S.P of the table = $1100 + \dfrac{10}{100}\times 1100=Rs.1210$
$\therefore$   The selling price of table is $Rs.1210$.

A fan is listed at Rs. $1400$ and the discount offered is $10\%$. What additional discount must be given to bring the net selling price to Rs. $1200$?

maths money math different discounts successive discounts problems on discounts

  1. $16\dfrac {2}{3}\%$

  2. $5\%$

  3. $4\dfrac {16}{21}\%$

  4. $6\%$

Show answer
Correct Option: C
Explanation:

M.P. $=$ Rs. $1400$, discount rate $= 10\%$
$\therefore$ Net price after $1^{st}$ discount $= 90\%$ of Rs. $1400$
$=\dfrac {90}{100}\times 1400=$ Rs. $1260$
Final selling price $=$ Rs. $1200$
$\therefore$ Additional discount $=$ Rs. $1260 -$ Rs. $1200 =$ Rs. $60$
$\therefore$ Additional discount rate $=\left (\dfrac {60}{1260}\times 100\right )\% =4\dfrac {16}{21}\%$

A pen is listed for Rs. $12$. A discount of $15\%$ is given on it. A second discount is given bringing the price down to Rs. $8.16$. The rate of second discount is

maths money math different discounts successive discounts problems on discounts

  1. $15\%$

  2. $18\%$

  3. $20\%$

  4. $25\%$

Show answer
Correct Option: C
Explanation:

M.P. $=$ Rs. $12$, discount rate $= 15\%$
$\therefore$ Net price after $1^{st}$ discount $=\dfrac {85}{100}\times  12=$ Rs. $10.20$
Final selling price $=$ Rs. $8.16$
$\therefore$ Additional discount $=$ Rs. $10.20-$ Rs. $8.16=$ Rs. $2.04$
$\therefore$ Additional discount rate $=\left (\dfrac {2.04}{10.20}\times 100\right )\% =20\%$.