Tag: money math

Questions Related to money math

After getting three equal successive discounts percentages over a marked price of Rs. $1000$ a customer has to pay $729$ for an article. What is the rate of each of the successive discounts ?

  1. $5$%

  2. $10$%

  3. $15$%

  4. $20$%


Correct Option: B
Explanation:

Let the discount price be$x$.

After the first discount, price$=(1-x)1000$
After the second discount, price$=(1-x)(1-x)1000=(1-x)^21000$
After the third discount, price$=(1-x)(1-x)(1-x)1000=(1-x)^3 1000$
According to the question 
$(1-x)^3 1000=729\(1-x)^3=729/1000\(1-x)=9/10\x=1/10$
Required percentage is $(1/10)\times 100=10\%$.

Find a single discount equivalent to following successive discounts : 
 of 20%, 10% and 5% in percent is

  1. $30$%

  2. $35$%

  3. $32$%

  4. $40$%


Correct Option: C
Explanation:

$ Assume MP =Rs 100$

After successive discounts $= 100 [1-\dfrac{20}{100}] [1-\dfrac{5}{100}][1-\dfrac{10}{100}]$

Discount from Marked Price $=100-68.4 =31.6$

% Discount $=\dfrac{31.6}{100} \times 100 =31.6$


The price of a VCR is marked as $Rs12000$. If successive discounts of $15\%$, $10\%$ and $5\%$ be allowed, then at what price does a customer buy it?

  1. $Rs.\ 8400$

  2. $Rs.\ 8721$

  3. $Rs.\ 8856$

  4. $None\ of\ these$


Correct Option: B
Explanation:

The marked price of VCR is $Rs.12000.$


Selling price = $85\%$ of $90\%$ of $95\%$ of $Rs.12000$

Selling price = $\dfrac{85}{100}\times \dfrac{90}{100}\times \dfrac{95}{100}\times 12000$

$\therefore$  Selling price $=Rs.8721$

$\therefore$  The price of VCR a customer buy is $Rs.8721.$

A refrigerator is offered for sale at Rs. 250.00 less successive discounts of 20% and 15%. The sale price of the refrigerator is :

  1. 35% less than Rs. 250.00

  2. 65% of Rs. 250.00

  3. 77% of Rs. 250.00

  4. 68% of Rs. 250.00

  5. none of these.


Correct Option: D
Explanation:

Sale Price = $250\left( 1-\cfrac { 20 }{ 100 }  \right) \left( 1-\cfrac { 15 }{ 100 }  \right) =250\left( \cfrac { 80 }{ 100 }  \right) \left( \cfrac { 85 }{ 100 }  \right) =250\left( \cfrac { 68 }{ 100 }  \right) $

$\therefore$ Sale Price = 68% of Rs. 250.00

Two discounts of $40\%$ and $20\%$ equal to a single discount of?

  1. $48\%$

  2. $53\%$

  3. $52\%$

  4. $60\%$


Correct Option: C

Two continuous discounts of $4$% on any thing should be equal to

  1. $9.00$%

  2. $7.02$%

  3. $7.84$%

  4. $8.08$%


Correct Option: C

A shopkeeper allows two successive discounts of 10% and 15% on his articles. If he gets Rs. 459 for an article, find it, marked price.

  1. Rs. $120$

  2. Rs. $300$

  3. Rs. $600$

  4. Rs. $800$


Correct Option: C
Explanation:

Let the Marked price be $ x $
After $ 10 $ % discount, the Selling price becomes $ 0.9 x$
After further $ 15 $ % discount, the selling price becomes $ 0.85 \times 0.9x = 0.765x $

Given, SP $ = Rs 459 $
$ => 0.765 = Rs 459 $
$ => x = Rs  600 $

Hence, marked price is $ Rs  600 $

A shopkeeper marks the price of an article at Rs. 800. Find the selling price, if he allows three successive discounts of 10%, 5% and 3%.

  1. Rs. 663.48

  2. Rs. 663.40

  3. Rs 663.28

  4. Rs 663.30


Correct Option: A
Explanation:

Marked Price of an article=Rs 800.
Price after 1st discount $=$ Rs $800-\cfrac { 10 }{ 100 } \times 800$
$=$Rs $720$
Price after 2nd discount $=$ Rs $720-\cfrac { 5 }{ 100 } \times 720$
$=$Rs $684$
Price after 3rd discount $=$ Rs $684-\cfrac { 3 }{ 100 } \times 684$
$=$ Rs $663.48$
Selling Price after three successive discounts $=$ Rs$ 663.48$

two successive discounts of 10% and 8% = 

  1. 17.2 %

  2. 18.2%

  3. 16.2%

  4. None of these


Correct Option: A
Explanation:

Let the original price =Rs.100

Discount=10% and 8%
Price after discount=$\dfrac{90}{100}\times \dfrac{8}{100}\times 100=82.80$
$\therefore Discount=100-82.80=17.2%$

The list price of a watch is Rs. 400. A customer gets two successive discounts, the first being 10%. Calculate, in percentage, the second discount, if the customer pays Rs. 306 for it.

  1. $11$%

  2. $13$%

  3. $15$%

  4. $18$%


Correct Option: C
Explanation:

Given the Marked price is $ Rs 400 $
After $ 10 $ % discount, the Selling price becomes $ 0.9  \times 400 = Rs   360  $
After further $ x $ % discount, the selling price becomes $ \dfrac { (100-x)}{100} \times 360 $

Given, SP $ = Rs 306 $
$ => \dfrac { (100-x)}{100} \times 360 =  306 $
$ => 100 - x = 85 $
$ => x = 15 $
Hence, 2nd discount is  is $ 15 $ %