Tag: p- block elements-ii

Questions Related to p- block elements-ii

Identify the gas that would form when hydrobromic acid is combined with nickel (II) sulfide.

  1. $NiBr _{2}$

  2. $H _{2}S$

  3. $HBr$

  4. $NiS$


Correct Option: B
Explanation:

The gas that would form when hydrobromic acid is combined with nickel (II) sulfide is $H _2S$

$2 HBr(aq) + NiS(s)\rightarrow H _2S + NiBr _2$.
Hence option B is correct.

When $KClO _3$ is heated in presence $MnO _2$ the product is:

  1. $O _2$

  2. $Cl _2$

  3. $O _3$

  4. none of these


Correct Option: A
Explanation:

When $KClO _3$ is reacted with $MnO _2$ in presence of heat it forms $KCl,O _2,MnO _2$ respectively.

$KClO _3+MnO _2\longrightarrow KCl+O _2+MnO _2$

Hence option A is correct.

Which of the following is most acidic?

  1. $HClO$

  2. $HClO _2$

  3. $HClO _3$

  4. $HClO _4$


Correct Option: D
Explanation:

As the oxidation number of chlorine(non metal) increases in the given acids the acidic nature of the compound increases. So the oxidation numbers of chlorine in the given compounds are $+1,+3,5,+7$ respectively.

So the acidic nature of $HClO _4$ is high.
Hence option D is correct.

A one litre flask is full of brown bromine vapour. Intensity of brown colour vapour will not decrease a appreciable amount on adding to flask some of:

  1. Piece of marble

  2. Carbon disulphide

  3. Carbon tetrachloride

  4. Animal charcoal powder


Correct Option: A
Explanation:

A one litre flask is full of brown bromine vapour. Intensity of brown colour vapour will not decrease a appreciable amount on adding to flask some of Piece of marble.

Hence option A is correct.

Fluorine is stronger oxidising agent than chlorine in water. The factor which is not responsible for that:

  1. Heat of dissociation

  2. e-affinity

  3. Heat of hydration

  4. Ionisation potential


Correct Option: B
Explanation:

Affinity do not have any relation with the efficiency of oxidizing ability.

Hence option A is correct.

$Br _2$ turns starch iodide paper :

  1. blue

  2. red

  3. colourless

  4. yellow


Correct Option: A
Explanation:

The bromine releases iodine from the potassium iodide Iodine reacts with starch to produce a blue color.

$Br _2+KI\rightarrow KBr+I _2$

Hence option A is correct

Which of the following reactions are not possible?

  1. $2NaCl+F _2$ $\longrightarrow \ $ $2NaF+Cl _2$

  2. $2NaCl+Br _2$ $\longrightarrow \ $ $2NaBr+Cl _2$

  3. $2NaF+Cl _2$ $\longrightarrow \ $ $2NaCl+F _2$

  4. $2NaBr+Cl _2$ $\longrightarrow \ $ $2NaCl+Br _2$


Correct Option: B,C
Explanation:

Option B and C reactions are not possible because the bromine do not displace chlorine and chlorine do not displace florine as chlorine and florine are most stable than bromine and chorine in their compounds respectively.

Hence option B,C are correct.

Iodine is oxidised by fuming nitric acid. The major product formed is:

  1. $HI$

  2. $HIO _2$

  3. $HIO _3$

  4. $HIO _4$


Correct Option: C
Explanation:

Reaction of iodine with fuming nitric acid is given by 

${ I } _{ 2 }+{ 10HNO } _{ 3 }\longrightarrow { 2HIO } _{ 3 }+{ 10NO } _{ 2 }+{ 4H } _{ 2 }O$.
So, the major product formed will be ${ HIO } _{ 3 }$.
So, correct answer is option $C$.

Which one of the following orders is not in accord with the property stated against it?

  1. $F _{2} > Cl _{2} > Br _{2}> I _{2}$ ; Oxidising power

  2. $HI > HBr > HCl > HF$ ; Acidic property in water

  3. $F _{2} > Cl _{2}> Br _{2} > I _{2}$; Electronegativity

  4. $F _{2}> Cl _{2} > Br _{2} > I _{2}$ ; Bond dissociation energy


Correct Option: D
Explanation:

The bond dissociation energies of $I _2$, $Br _2$ and $Cl _2$ increase in the following order:

$I _2$ < $Br _2$ < $Cl _2$ 

In case of $F _2$, the bond dissociation energy is lower than that of $Cl _2$ and $Br _2$ because of the existence of strong inter-electronic repulsions owing to its small size. The overall trend of bond dissociation energies is thus as follows:
$I _2$ < $F _2$ < $Br _2$ < $Cl _2$ 

Which of the following compounds is used as a sedative (sleep-inducing substance)?

  1. Sodium Chloride

  2. Potassium bromide

  3. Calcium Chloride

  4. Phosphorous trichloride


Correct Option: B
Explanation:

Potassium bromide ($KBr$) is a salt, widely used as an anticonvulsant and a sedative in the late 19th and early 20th centuries.

Its action is due to the bromide ion (sodium bromide is equally effective).
Hence option B is correct answer.