Tag: p- block elements-ii

Questions Related to p- block elements-ii

Which of the following is true for $N _{2}O _{5}$?

  1. Paramagnetic

  2. Anhydride of $HNO _{2}$

  3. Brown gas

  4. Exist in solid In form of $[NO^{+} _{2}][NO _{3}^{-}]$


Correct Option: D
Explanation:

$N _{2}O _{5}$ in solid form exists as $NO _{3}^{-}$ and $NO _{2}^{-}$.

Which forms $p\pi - p \pi$ multiple bonds with itself and with C and O?

  1. P, As

  2. N, As

  3. N, P

  4. N


Correct Option: D
Explanation:

N forms such bonds as,
$N \equiv N;  -C \equiv N;  N\equiv O$

Nitrogen differs from P, As, Sb and Bi in the following properties :

  1. It forms diatomic molecule.

  2. It is not able to extent its coordination number beyond four.

  3. Nitrogen does not function as a Lewis acid whereas P, As, Sb and Bi do so.

  4. In all the properties given above.


Correct Option: D
Explanation:

As vacant d-orbital are present in P and other elements of this group except N so they can expand their valency and forms stable pentavalence product but due to absence of d-orbitals nitrogen cannot form pentavalence products.

It forms diatomic molecule $N _2$.
Nitrogen does not function as a Lewis acid due to absence of d-orbitals and it is a Lewis base due to presence of lone pair.

The anomalous behaviour of nitrogen is due to:

  1. small size and high electronegativity

  2. non availability of d-orbitals in valency shell

  3. ease of multiple bond formation

  4. all are correct


Correct Option: D
Explanation:

Nitrogen differs from other members of the group due to its smaller size, high electronegativity, high IE and non availability of d-orbitals. Nitrogen has unique ability to form $p\pi - p\pi $ multiple bonds with itself and with other elements having small size and high electronegativity.

An element X combines with hydrogen to form a compound $XH _3$. The element X is placed on the right side ofthe periodic table. What is true about the element X?
A. Has 3 valence electrons.
B. Is a metal and is solid.
C. Is a non-metal and is a gas.
D. Has 5 valence electrons.
E. $XH _3$  reacts with water to form a basic compound?

  1. A, B and C

  2. B,C and D

  3. C, D and E

  4. E, A and B


Correct Option: C
Explanation:

Here, $X$ is nitrogen with atomic number 7 and electronic configuration $ { 1s }^{ 2 }{ 2s }^{ 2 }{ 2p }^{ 3 } $ 

It is a non metal belonging to group 15.
Solution of ammonia In water is alkaline in nature and is highly soluble in water.

In atoms of nitrogen molecule, which type of bond are present ?

  1. Hydrogen bond

  2. Ionic bond

  3. Polar covalent bond

  4. Nonpolar covalent bond

  5. Metallic bond


Correct Option: D
Explanation:

In atoms of nitrogen molecule, nonpolar covalent bonds are present.
Nonpolar covalent bond is formed between two atoms having zero electronegativty difference.

Identify the true statement regarding nitrates of all metals.

  1. All nitrates decompose to give $N{ O } _{ 2 }$

  2. All nitrates are soluble in water

  3. All nitrates are insoluble in water

  4. All nitrates are stable to heat


Correct Option: B
Explanation:

Nitrates of divalent and trivalent metals (Mg, Ca, Ba, Pb, Cu, Zn, Hg, Al, Fe etc.) decompose on heating to give reddish brown fumes of nitrogen dioxide.

The nitrates, chlorates, and acetates of all metals are soluble in water.

Nitrates are not stable to heat they decompose to release nitrogen dioxide.


Which molecule is relatively more stable?

  1. $O _2$

  2. $H _2$

  3. $Li _2$

  4. $N _2$


Correct Option: D
Explanation:

Nitrogen molecule ($\displaystyle N _2$) is relatively more stable. Each $N$ atom has completed its octet and there is a triple bond between two $N$ atoms. In other molecules, there is either a single bond or a double bond between two atoms. A triple bond is stronger than a single or double bond.

The impurities formed during laboratory preparation of dinitrogen from ammonium chloride and sodium nitride is/are:

  1. $HCl$

  2. $HNO _3  and NO $

  3. $NO _2$

  4. $HNO _2$


Correct Option: B,C
Explanation:

$NH _4Cl+NaNO _2 \rightarrow N _2+NaCl+2H _2O$

The impurities formed are small amount of $NO$ and $HNO _3$ , which can be removed by passing gas through aqueous sulphuric acid containing potassium dichromate.

What results in the weak catenation property of nitrogen?

  1. Smaller size

  2. Repulsion between non-bonded electrons

  3. Repulsion between protons

  4. High electronegativity


Correct Option: B
Explanation:

The weak catenation property of nitrogen is due to lone pair repulsion of lone pair of electrons on nitrogen molecule.