Tag: standardized measurement

Questions Related to standardized measurement

Which of the following pairs is not matched?

physics measurements and units kinds of units fundamental quantities standardized measurement

  1. Coefficient of self-induction : henry

  2. Magnetic flux : weber

  3. Electric flux : volt-meter

  4. Electric capacity : farad-meter

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Correct Option: D
Explanation:

Electric capacitance of a conductor is the ability with which the conductor can hold the charge.
In SI system, unit of capacitance is farad($F$).
Hence, option D is not matched.

kilowatt-hour is the unit of ____. 

physics measurements and units kinds of units fundamental quantities standardized measurement

  1. potential difference

  2. electric power

  3. electric energy

  4. charge

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Correct Option: C
Explanation:

$\text{Kilowatt hour}$ is the $commercial$ unit of $electrical$ ENERGY.

As the power$(means $ $ \dfrac{Work}{time}=\dfrac{energy}{time})$
so $energy=power\times time $

$\text{so unit of energy= unit of power *unit of time =watt *second }$
Kilowatt-hour is just $3600\times 1000$ times  of the above value of energy.

Oersted is the unit of

physics measurements and units kinds of units fundamental quantities standardized measurement

  1. Intensity of magnetisation

  2. Magnetic moment

  3. Magnetic induction

  4. Magnetic flux

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Correct Option: A
Explanation:

The intensity of magnetic field at a point on the field is defined as the force on a unit north pole placed at that point.
Intensity of magnetization is measured in Oersted as a unit.

The SI unit of pressure is

physics measurements and units kinds of units fundamental quantities standardized measurement

  1. $Newton$

  2. $Joule$

  3. $N/m^{2}$

  4. $Nm$

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Correct Option: C
Explanation:

Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed. It is defines as force per unit area. The SI unit of pressure is $N/m^2$.

The damping force on an oscillator is directly proportional to the velocity. The units of constant of proportionality are

physics measurements and units kinds of units fundamental quantities standardized measurement

  1. Kg m/s

  2. Kg $m/s^2$

  3. Kg/s

  4. kgs

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Correct Option: C

The unit of permittivity of free space, $ \varepsilon _ o $ is

physics measurements and units kinds of units fundamental quantities standardized measurement

  1. $\dfrac {Coulomb} {newton - meter}$

  2. $ \dfrac {newton - meter^2} { Coulomb ^2} $

  3.  $\dfrac {Coulomb^2}{newton- meter^2} $

  4. $ \dfrac {Coulomb^2} {(newton-metre)^2}$

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Correct Option: B

In $S = a + bt + ct^{2}, S$ is measured in metres and $t$ is seconds. The unit of $c$ is

physics measurements and units kinds of units fundamental quantities standardized measurement

  1. $ms^{-2}$

  2. $m$

  3. $m^{-1}$

  4. None

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Correct Option: A

If the volume of a cube is equal to its surface area in magnitude. Then the volume of the cube is? 

physics measurements and units kinds of units fundamental quantities standardized measurement

  1. $216$ unit

  2. $512$ unit

  3. $64$ unit

  4. None of these

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Correct Option: A
Explanation:

Let us take side of cube$=a$
then  $a^3=6a^2$
$\therefore a=6$
So volume of cube is:

$a^3=(6)^3=216$ units

In the eqn. $\left (P+\dfrac {a}{V^2}\right )(V-b)=$ constant, the unit of $a$ is

physics measurements and units kinds of units fundamental quantities standardized measurement

  1. $dyne\times cm^5$

  2. $dyne\times cm^4$

  3. $dyne/cm^3$

  4. $dyne\times cm^2$

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Correct Option: B
Explanation:

Units of both $P $ and $ \dfrac {a}{V^2}$ must be same.
So, $\dfrac {a}{V^2}=P$  $\implies   a=PV^2$ 

Since unit of $P$ is $dyne \ cm^{-2}$ and that of $V$ is $cm^3$.
$\therefore$ Unit of a is  $\dfrac {dyne}{cm^2}(cm^3)^2=dyne\times cm^4$

Unit of specific resistance is

physics measurements and units kinds of units fundamental quantities standardized measurement

  1. $\Omega/m^2$

  2. $\Omega m^3$

  3. $\Omega m$

  4. $\Omega/m$

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Correct Option: C
Explanation:

Specific resistance of a material is given by

$\rho =\displaystyle \frac {RA}{l}$

Substitute the unit in the above expression:
$\rho=\dfrac {\Omega.m^2}{m}=\Omega m$