Tag: standardized measurement

Questions Related to standardized measurement

Which system of units has been taken as standard?

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. M.K.S

  2. C.G.S

  3. Both

  4. None

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Correct Option: A
Explanation:

In S.I system (standard international system), the units of mass,length and time are same,as that of M.K.S system. However , it is an enlarged system encompassing all fundamental units.

MKS system means

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. Millimeter, kilometre, seconds

  2. Metre, kilogram, seconds

  3. Millisecond, kilolitre, seconds

  4. Milligram, kilogram, seconds

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Correct Option: B
Explanation:

In MKS system,M stands for metre (length),K stands for kilogram(mass) and S stands for seconds(time).

Units of Planck's constant in CGS system are:

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. Erg per second

  2. Second per erg

  3. Erg second

  4. Erg per second per second

Show answer
Correct Option: C
Explanation:

Planck's constant, symbolized h, relates the energy in one quantum (photon) of electromagnetic radiation to the frequency of that radiation.  In the centimeter-gram-second (CGS) or small-unit metric system, it is equal to approximately $6.626176\times 10^{-27}\,$Erg Second.

If force (F), work (W) and velocity (V) are taken as fundamental quantities then the dimensional formula of time (T) is

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. $\left[ { W }^{ 1 }{ F }^{ 1 }{ V }^{ 1 } \right] $

  2. $\left[ { W }^{ 1 }{ F }^{ 1 }{ V }^{ -1 } \right] $

  3. $\left[ { W }^{ -1 }{ F }^{ -1 }{ V }^{ -1 } \right] $

  4. $\left[ { W }^{ 1 }{ F }^{ -1 }{ V }^{ -1 } \right] $

Show answer
Correct Option: D
Explanation:
We know,

$[W]=ML^2T^{-2}$

$[F]=MLT^{-2}$

$[V]=LT^{-1}$

Let,
$W^aF^bV^c=M^0L^0T$

$a+b=0$

$2a+b+c=0$, $a+c=0$

$-2a-2b-c=1$

$c=-1,a=1,b=-1$

Hence , $[T]=[WF^{-1}V^{-1}]$

Option $\textbf D$ is the correct answer

The ratio of SI unit to CGS unit of G is

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. $10^{3}$

  2. $10^{2}$

  3. $10^{-2}$

  4. $10^{-3}$

Show answer
Correct Option: A
Explanation:
SI unit of G is  $\dfrac{N m^2}{kg^2}$.
CGS unit of G is  $\dfrac{dyne \ cm^2}{gm^2}$
We know that  $1 \ N = 10^5 \ dyne$ and $1 \ m = 10^2 \ cm$ and $1 \ kg = 10^3 \ gm$
So ratio of SI unit to CGS unit   $ = \dfrac{\dfrac{N  \ m^2}{kg^2}}{\dfrac{dyne \ cm^2}{gm^2}} = \dfrac{\dfrac{10^5 \ dyne \ (10^2 \ cm)^2}{(10^3 \ gm)^2}}{\dfrac{dyne \ cm^2}{gm^2}} = 10^3$
Correct answer is option A.

Which of the following represents the magnitude of a temperature correctly?

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. 10 k

  2. 10 Kelvins

  3. 10 Ks

  4. 10 K

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Correct Option: D
Explanation:
Temperature is measured in Kelvin which is represented by $K$
Thus, $10 \ K$ is the correct representation of temperature.

1 Newton $=$

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. $10^4 dyne$

  2. $10^5 dyne$

  3. $10^6dyne$

  4. $10^7 dyne$

Show answer
Correct Option: B
Explanation:
S.I. unit of force is Newton and CGS unit of force is done.

We know $F=ma$
so, force can be expresses in S.I. Units as $Kg m s^{-2}$
and dyne can be expressed as $gcms^{-2}$
1 Newton= $kg ms^{-2}$ 
                 =$10^3 g*10^2 cms  s^{-2}$
                 =$10^5 g cm s^{-2}$
                 =$10^5 dyne$

The SI unit of specific latent heat is 

physics measurements and units kinds of units fundamental quantities standardized measurement

  1. $Jkg^{-1}K^{-1}$

  2. $J^{0}K^{-1}$

  3. $J kg^{-1}$

  4. $J kgK^{-1}$

Show answer
Correct Option: C
Explanation:

The specific latent heat of a substance is the quantity of heat energy required to change the state of a unit mass of a substance.

${E} _{L}= ml$

here ${E} _{L}$ is the heat transferred, in joules,m is the mass, in kilograms, and l is the latent heat in joules per kilogram.

The SI unit for specific latent heat is $J{kg}^{-1}$.

The specific heat capacity of water in SI unit is :

physics measurements and units kinds of units fundamental quantities standardized measurement

  1. $4.2 Jg^{-1}K^{-1}$

  2. $42 Jg^{-1}K^{-1}$

  3. $420 J kg^{-1}K^{-1}$

  4. $4200 J kg^{-1}K^{-1}$

Show answer
Correct Option: D
Explanation:

The specific heat capacity  of a substance is the heat needed to raise

the temperature of 1 kg of the substance by 1K (or by ${1}^{0}C$).
The specific heat capacity of water is $4200 J{kg}^{-1}{K}^{-1}$.

The SI unit of thermal capacity is ;

physics measurements and units kinds of units fundamental quantities standardized measurement

  1. $J\ kg^{-1}\  K^{-1}$

  2. $J^{-1}\ kg\ K^{-1}$

  3. $JK^{-1}$

  4. $J\  kg\ K^{-1}$

Show answer
Correct Option: C
Explanation:


The heat or thermal capacity of a defined system is the amount of heat required to raise the system's temperature by one degree. It is expressed in units of thermal energy per degree temperature.

$q= C\times t$

$C=\dfrac{q}{\triangle t}$

here,$C=$heat or thermal capacity
        $q=$heat required (J)
        $\triangle t={t} _{1}-{t} _{2}$ (K)

so,The S.I. unit of heat or thermal capacity is $J{K}^{-1}$