Tag: comparing decimals

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Questions Related to comparing decimals

Multiple choice maths decimal numbers comparing and ordering of decimals more or less comparing decimals

Find the greater number.
$256.356,256.869$

  1. $256.356$
  2. $256.869$

  3. Both are equal

  4. None
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Since the decimal $0.869$ is greater then another decimal number $0.356$ because of the fact that $869>356$.


Also since, the number before the decimals is same in the given numbers that is $256$, therefore, we conclude that $256.869>256.356$

Hence, the greater number is $256.869$.

Multiple choice maths decimal forms comparing and ordering of decimals more or less comparing decimals

Find the values of each of the following correct to three places of decimals, it being given that $ \sqrt{2}=1.4142, \sqrt{3} = 1.732, \sqrt{5} = 2.2360, \sqrt{6} = 2.4495$ and $\sqrt{10} = 3.162.$ 


$\dfrac{1+\sqrt{2}}{3-2\sqrt{2}}$

  1. 14.0710

  2. 24.10710

  3. 16.0213

  4. None of the above
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
Given,

$\dfrac{1+\sqrt 2}{3-2 \sqrt 2}$

$=\dfrac{1+\sqrt 2}{\sqrt 3 \times \sqrt 3-\sqrt 2 \times \sqrt 2 \times \sqrt 2}$

$=\dfrac{1+1.4142}{1.732 \times 1.732-1.4142 \times 1.4142 \times 1.4142}$

$=14.0710$
Multiple choice maths decimal forms comparing and ordering of decimals more or less comparing decimals

Find the value of the following correct to three places of decimals, it being given that $ \sqrt{2}=1.4142, \sqrt{3} = 1.732, \sqrt{5} = 2.2360, \sqrt{6} = 2.4495$ and $\sqrt{10} = 3.162.$ 


$\dfrac{3-\sqrt{5}}{3+2\sqrt{5}}$

  1. 0.102

  2. 2.1102

  3. 1.1002

  4. None of the above
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
Given,

$\dfrac {3-\sqrt 5}{3+2\sqrt{5}}$

$=\dfrac {\sqrt{3}\times \sqrt{3}-\sqrt 5}{\sqrt{3}\times \sqrt{3}+\sqrt{2}\times \sqrt{2} \times \sqrt{5}}$

$=\dfrac {1.732\times 1.732-2.2360}{1.732\times 1.732+1.4142\times 1.4142 \times 2.2360}$

$=0.102$