Tag: comparing decimals

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Questions Related to comparing decimals

Multiple choice maths decimal numbers comparing and ordering of decimals more or less comparing decimals

Which of the following expressions is CORRECT?

  1. $0.6 < 0.06$
  2. $0.66=\displaystyle\frac{5}{9}$
  3. $455 > \displaystyle\frac{11}{25}$
  4. $\displaystyle\frac{1}{6} > 0.17$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

(A) $0.6 > 0.06$

As we can see, LHS and RHS are same i.e. $0.6$. So, $=$ sign must be there in between. So, this statement is false.
(B) $0.66=\displaystyle\frac{66}{100}=\frac{33}{50}\neq \frac{5}{9}$
This statement is also false.
(C) $\displaystyle 455 >\frac{11}{25}=0.44$
This ststement is true.
(D) $\displaystyle\frac{1}{6}=0.166 < 0.17$
This statemnt is also false.
So, correct answer is option C.

Multiple choice maths decimal numbers comparing and ordering of decimals more or less comparing decimals

Select the correct option which make the given expression true.
$12.5+5\displaystyle\frac{3}{8}+8\frac{1}{8}+9\frac{4}{5}+\square 2.9+15-6.88+11.08$.

  1. $<$
  2. $>$
  3. $=$

  4. Can't be determined
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

We have, $\displaystyle 12.5+5\frac{3}{8}+8\frac{1}{8}+9\frac{4}{5}$

$=12.5+\dfrac{43}{8}+\dfrac{65}{8}+\dfrac{49}{5}$
$=12.5+5.375+8.125+9.8=35.8$ 
Now lets check for $2.9+15-6.88+11.08=22.1$
Since, $35.8 > 22.1$
Therefore, $ 12.5+\displaystyle 5\frac{3}{8}+8\frac{1}{8}+9\frac{4}{5} > 2.9+15-6.88+11.08$.

Multiple choice maths decimal numbers comparing and ordering of decimals more or less comparing decimals

Which of the following numbers $0.1, 0.11,$ $\displaystyle \left ( 0.11 \right )^{2},\sqrt{0.0001}$ is the greatest ?

  1. $0.11$
  2. $0.1$
  3. $0.11^2$

  4. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
Consider the given numbers and find their values as follows:

$0.10\\ 0.11\\ \left( 0.11 \right) ^{ 2 }=0.11\times 0.11=0.0121\\ \sqrt { 0.0001 } =\sqrt { \dfrac { 1 }{ 10000 }  } =\sqrt { \dfrac { 1^{ 2 } }{ 100^{ 2 } }  } =\dfrac { 1 }{ 100 } =0.010$

Now from the above values we conclude that:

$0.11<0.10<0.0121<0.010$

Hence, $0.11$ is the greatest number.