Tag: the periodic table

Questions Related to the periodic table

Atomic wt. of P is 31 and Sb is 120. What will be the atomic wt. of As, as per Dobernier triad rule?

  1. $151$

  2. $75.5$

  3. $89.5$

  4. Unpredictable


Correct Option: B
Explanation:

Atomic wt. of P is 31 and Sb is 120. The atomic wt. of As, as per Dobernier triad rule will be average of two. It will be $\displaystyle \frac {31+120}{2} = \frac {151}{2} =75.5 $

Atomic wt. of $Cl = 35.5$ and of $I = 127$. According to Doeberiner triad rule atomic wt. of $Br$ will be:

  1. $80.0$

  2. $162.5$

  3. $81.25$

  4. $91.5$


Correct Option: C
Explanation:

Atomic wt. of Cl = 35.5 and I = 127.


According to Doberiner triad rule:

Br =$\dfrac {35.5 +127}{2}=\dfrac {162.5}{2}=81.25$

Hence, the correct option is $\text{C}$

If three elements X, Y, and Z form a Dobereiner's triad and atomic weights of X and Z are 9 and 40 respectively, then the atomic weight of the element Y is approximately:

  1. 24.5

  2. 49

  3. 34.5

  4. 29


Correct Option: A
Explanation:

According to Dobereiner, the atomic weight of the central element of the triad is the arithmetic mean of the atomic weights of the other two members. 


Therefore, atomic weight of Y = $\cfrac{9 + 40}{2} = 24.5\ g$


Hence, option A is correct.

Law of Triad was proposed by:

  1. Newland

  2. Gay Lussac

  3. Mendeleev

  4. Dobereiner


Correct Option: D
Explanation:

Dobereiner, in 1817 suggested a relationship between the properties of elements and their atomic weights. According to Dobereiner, the atomic weight of the middle element is nearly the same as average of the atomic weights of other two elements.

The element in between lithium and potassium in Dobereiner's classification is:

  1. Mg

  2. Na

  3. Ca

  4. Rb


Correct Option: B
Explanation:

Li, Na, K formed a Dobereiner's triad. Thus the element between Lithium and potassium is Sodium (Na).

Chlorine, Y and Iodine form a Dobereiner's triad. Identify the atomic weight of Y.

  1. 162.5

  2. 81.25

  3. 121.5

  4. 90.5


Correct Option: B
Explanation:
Cl, Y and I for Dobereiner's triad. Thus weight of Y is arrange of weight of Cl and I
$\therefore$ Atomic weight of Y is $\cfrac { 35.5+127 }{ 2 } =81.25$

Three elements X, Y and Z form a Dobereiner triad. The ratio of the atomic weight of X to that of Z is 7: 25.


 If the sum of the atomic weights of X and Z is 160, find the atomic weights of X, Y and Z.

  1. X $\rightarrow$ 35, Y $\rightarrow$ 80, Z $\rightarrow$ 125

  2. X $\rightarrow$ 125, Y $\rightarrow$ 80, Z $\rightarrow$ 35

  3. X $\rightarrow$ 80, Y $\rightarrow$ 35, Z $\rightarrow$ 125

  4. X $\rightarrow$ 80, Y $\rightarrow$ 125, Z $\rightarrow$ 35


Correct Option: A
Explanation:
Let weight of X be $7a$  $\therefore$ Atomic weight of $Z=25a$

$\therefore7a+25a=160$

$\Rightarrow a=5$

Weight of X$=35$ and of Z is $125$

Atomic weight of Y is arranged of X and $2=\cfrac { 35+125 }{ 2 } =80$

Hence, the correct option is $\text{A}$

When a Dobereiner triad is considered, the sum of atomic weights of extreme elements X and Z is 177.6 and difference of Z and Y is five times the number of protons present in a neon atom. Identify X, Y and Z.

  1. $X \rightarrow Ca, Y \rightarrow Sr, Z \rightarrow Ba$

  2. $X \rightarrow Li, Y \rightarrow Na, Z \rightarrow K$

  3. $X \rightarrow K, Y \rightarrow Rb, Z \rightarrow Cs$

  4. $X \rightarrow Sr, Y \rightarrow Ba, Z \rightarrow Ra$


Correct Option: A
Explanation:
The atomic weight of Y is avergae of X and Z
$\therefore { M } _{ Y }=\cfrac { 177.6 }{ 2 } =88.8$
$88.8$ is weight of Sr. So Y is Sr. According to this only option A is correct.

Which of the following sets of atomic masses do not correspond to Dobernier traid?

  1. $7, 23, 39$

  2. $20, 38, 56$

  3. $47, 91, 178$

  4. $54, 95, 183$


Correct Option: C,D
Explanation:

The following sets of atomic masses do not correspond to Dobernier traid.
(C) $\displaystyle 47, 91, 178$
(D) $\displaystyle 54, 95, 183$
In these sets, the atomic mass of middle element is not equal to the mean of atomic masses of first and last element.
$\displaystyle 91 \neq \dfrac {47+178}{2}$
$\displaystyle 95 \neq \dfrac {54+183}{2} $

Dobereiner was the first person to illustrate the relationship between the ____________ of elements and their properties.

  1. atomic masses

  2. electron negativity

  3. molecular masses

  4. number of protons


Correct Option: A
Explanation:

Dobereiner grouped elements in set of triads. Thus each group had 3 elements. Dobereiner classified elements into groups based on their properties. He illustrate the relationship between the atomic masses of elements and their properties with his law of triads.