Tag: measuring temperature

Questions Related to measuring temperature

Multiple choice physics heat - measurement sources of heat introduction to heat measuring temperature

During burning of a candle, different zones of combustion in the flame are listed below:

A. outermost zone
B. innermost zone
C. middle zone
The correct order of temperature of zones is :

  1. $A > B > C$

  2. $C > B > A$

  3. $B > C > A$

  4. $A > C > B$

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The correct order of temperature of zones of candle flames is -
Outermost zone > Middle zone > innermost zone.
Because outerzone will have the highest temperature and inner zone will have the least temperature.

Multiple choice physics heat - measurement sources of heat introduction to heat measuring temperature

At what temperature is the Fahrenheit scale reading equal to twice of Celsius ?

  1. $ 40^0C $

  2. $ 160^0C $

  3. $ 80^0C $

  4. $ 100^0C $

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

We know the relation between Fahrenheit scale and degree celsius,


$\dfrac{C-0}{100}=\dfrac{F-32}{180}$

Given,

$F=2C$

Then,

$\dfrac{C}{100}=\dfrac{2C-32}{180}$

$\dfrac{C}{100}=\dfrac{C-16}{90}$

$\implies 9C=10C-160$

$\implies C=160^0C$

Multiple choice physics measurement and effects of heat sources of heat introduction to heat measuring temperature

A man wishes to fit an aluminium ring on steel rod of 1 cm diameter and found it is 0.01 cm smaller in diameter. How much should the on temperature be raised before it just slips on the
$(\alpha _A = 25 \times 10^{-6}/^oC;$ $10 \times 10^{-6}/^oC)$

  1. $40^oC$

  2. $50^oC$

  3. $25^oC$

  4. $60^oC$

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

${l _2} = {l _1}\left( {1 + {\alpha _A}\Delta T} \right)$

${l _2} = {l _1} + {l _1}{\alpha _A}\Delta T$

$\displaystyle {{{l _2} - {l _1}} \over {{l _1}}} = {\alpha _A}\Delta T$

$\displaystyle {{0.01 \times {{10}^{ - 2}}} \over {1 \times {{10}^{ - 2}} \times 25 \times {{10}^{ - 6}}}} = \Delta T$

$\Delta T = {40^0}C$