Tag: botany

Questions Related to botany

Dichotomous branching occurs in

  1. Liverworts

  2. Funaria

  3. Dryopteris

  4. Pinus


Correct Option: A

Sphaerocarpos belongs to 

  1. Bryophyta

  2. Pteridophyta

  3. Gymnosperms

  4. Angiosperms


Correct Option: A
Explanation:

Sphaerocarpos is a genus of liverwort. Division bryophyta is divided into three classes namely, Hepaticopsida (liverwort), Anthoceropsida and Bryopsida. Liverwort is divided into four orders namely, Marchantiales (example: Riccia), Sphaerocarpales (example: Sphaerocarpos), Jungermanniales (example: Pellia) and Calobryales (example: Calobryum).

Thus, the correct answer is option A.

Archegoniophore occurs in

  1. Chara

  2. Funaria

  3. Adiantum

  4. Marchantia


Correct Option: D
Explanation:

Archegoniophore is a stalk of a prothallium on which archegonia grows. Marchantia is a genus of liverworts. The thallus of Marchantia is dioecious in nature. It produces either female archegoniophores or male antheridiophores. 

Thus, the correct answer is option D.

Areolated thallus is characteristic of

  1. Funaria hygrometrica

  2. Polytrichium commune

  3. Marchantia

  4. Porella pelatyphylla


Correct Option: C
Explanation:

The upper part of the thallus shows well-developed air chambers bounded on all sides by plates of cells, below by the storage tissue and roofed in by an epidermal layer of cells; each chamber is open to the air by a simple pore.

The product of the light reaction of photosynthesis which is not common between cyclic and non-cyclic photophosphorylation and is not utilised in the Calvin cycle is 

  1. O$ _2$

  2. ATP

  3. $NADPH _2$

  4. O$ _2$ and ATP


Correct Option: A
Explanation:

In cyclic phosphorylation, oxygen is not evolved as the by-product where as, oxygen is evolved as a by-product during non-cyclic phosphorylation. Calvin cycle is the second stage of photosynthesis in which carbon atoms from carbon dioxide are combined, using the energy in ATP and NADPH, to make glucose.

So, the correct option is 'O$ _{2}$'.

How many quanta of lights are required to evolve one oxygen molecule in photosythesis?

  1. Three

  2. Eight

  3. Four 

  4. Two


Correct Option: B
Explanation:
 The quantum of light required in photosynthesis is 8 photons for one molecule of oxygen to be evolved. In this, 4 photons are required by photosystem II and 4 by photosystem I. The equation for the same is, 
2 x 2H$ _2$O --> 4H$^+$ + O$ _2$ + 4 electrons. 
Thus, the correct answer is 'Eight.'

During the light phase of photosynthesis .......... is oxidized and .......... is reduced.

  1. $CO _2$ and Water

  2. Water and $CO _2$

  3. Water and $NADP$

  4. $NADPH _2$ and $CO _2$


Correct Option: C
Explanation:

The light reaction takes place in thylakoid discs. There, water is oxidized and oxygen is released. The hydrogen is accepted by $NADP$ and hence get reduced to $NADPH _2$. 

So the correct answer is 'water and $NADP$' respectively.

Which of the following process is supported by photolysis?

  1. Oxidation

  2. Reduction

  3. Electroporation

  4. Transformation


Correct Option: A
Explanation:

Photolysis is the process of breakdown of water molecule in the presence of sunlight. It results in the release of oxygen and hydrogen. It is also called as photodecomposition. It occurs during photosynthesis in a series of light-driven oxidation events. In this, water absorbs photons and the energy released during this process drives oxidation processes induced by light. 

Thus, the correct answer is 'Oxidation.'

Which one is not include in photochemical phase

  1. Light absorption

  2. Photophosphorylation

  3. $H _2O$ spliting

  4. $CO _2$ reduction


Correct Option: D
Explanation:
The photochemical phase of photosynthesis, also known as light reaction includes absorption of light by chlorophyll molecules, splitting of water to generate electrons along with release of oxygen and photophosphorylation to generate ATP.

So, the correct answer is, 'CO2 reduction'.

Which statement is correct for given reaction for photosynthesis?


$ 2 H _2 A + CO _2 \xrightarrow []{light} 2A + CH _2 O + H _2 O $

  1. $H$ donor is oxidisable substrate

  2. $O _2 $ evolve from $H _2 O $ if reducible compound is $H _2 O $

  3. Glucose gain its oxygen from $H _2 O $

  4. Both A and C


Correct Option: A
Explanation:

The light reaction of the photosynthesis starts when the chlorophyll loses its electron after absorbing the light. In order to maintain the continuity of the reaction, there is a requirement of an oxidizable substance that can donate its electron to the chlorophyll. Water acts as the electron donor through a process called photolysis of water. In this process, the oxygen is also released as a by-product.

A. In the given equation H donor is an oxidizable substrate that happens to be water.
B. O$ _{2}$ is evolved from water but it is not reducible compound.
C. Glucose in oxygen comes from the carbon dioxide and not water. The oxygen from water is released as a by-product of the reaction.
Hence, the correct answer is 'H donor is oxidizable substrate'.